Class 5 Maths Chapter 4 Solutions: We the Travellers

Question-by-question working

Read the prompt, attempt it, then check each step

Every exercise subpart and table row is a separate item. Shared figures and table headings are repeated whenever they are needed to understand the question.

Detailed worked answers

Textbook page 42

Textbook page 42 · solved item 1

NCERT Class 5 Maths Chapter 4, solved question 1 — Question from the current NCERT textbook

In puzzle (a), interchange the least number of pairs to make both group sums equal.

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Step 1: The left group totals 19 and the right group totals 21, so the left side needs to gain 1 while the right side loses 1.
Step 2: Interchange 2 from the left with 3 from the right. The two totals become 19-2+3=20 and 21-3+2=20.
Answer: Interchange 2 and 3. Both groups then have sum 20.

Textbook page 42 · solved item 2

NCERT Class 5 Maths Chapter 4, solved question 2 — Question from the current NCERT textbook

In puzzle (b), interchange the least number of pairs to make both group sums equal.

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Step 1: The left group totals 39 and the right group totals 47, so each final group must total 43.
Step 2: Interchange 5 from the left with 9 from the right. The left gains 4 and the right loses 4.
Answer: Interchange 5 and 9. Both groups then have sum 43.

Textbook page 42 · solved item 3

NCERT Class 5 Maths Chapter 4, solved question 3 — Question from the current NCERT textbook

In puzzle (c), interchange the least number of pairs to make both group sums equal.

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Step 1: The two sums are 68 and 76, so both must become 72.
Step 2: Interchange 11 with 13 and 15 with 17. Together, these moves add 4 to the left and remove 4 from the right.
Answer: Two pair interchanges work: 11\leftrightarrow13 and 15\leftrightarrow17. Both sums become 72.

Textbook page 42 · solved item 4

NCERT Class 5 Maths Chapter 4, solved question 4 — Question from the current NCERT textbook

In puzzle (d), interchange the least number of pairs to make both group sums equal.

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Step 1: The two sums are 314 and 330, so both must become 322.
Step 2: Interchange 77 with 81 and 78 with 82. Each interchange adds 4 to the left, for a total gain of 8.
Answer: These two pair interchanges make both group sums 322.

Detailed worked answers

Textbook page 43

Textbook page 43 · solved item 5

NCERT Class 5 Maths Chapter 4, solved question 5 — Question from the current NCERT textbook

A lorry has 28 litres of fuel and 75 more litres are filled. How much fuel is there now?

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Step 1: Add the ones: 8+5=13. Write 3 ones and regroup 10 ones as 1 ten.
Step 2: Add the tens: 2+7+1=10 tens, which is 1 hundred and 0 tens.
Answer: 28+75=103. The lorry has 103 litres of fuel.

Textbook page 43 · solved item 6

NCERT Class 5 Maths Chapter 4, solved question 6 — Question from the current NCERT textbook

Find the sum of 49 and 89.

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Step 1: Add the ones: 9+9=18. Write 8 and regroup 1 ten.
Step 2: Add the tens: 4+8+1=13 tens.
Answer: 49+89=138.

Textbook page 43 · solved item 7

NCERT Class 5 Maths Chapter 4, solved question 7 — Question from the current NCERT textbook

Find the sum: 15+79.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add 5 and 9 to get 14; write 4, regroup 1 ten, then add the tens to get 9 tens.
Answer: 15+79=94.

Textbook page 43 · solved item 8

NCERT Class 5 Maths Chapter 4, solved question 8 — Question from the current NCERT textbook

Find the sum: 46+99.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Use 99=100-1: 46+100=146, then take away 1 to get 145.
Answer: 46+99=145.

Textbook page 43 · solved item 9

NCERT Class 5 Maths Chapter 4, solved question 9 — Question from the current NCERT textbook

Find the sum: 38+35.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add the ones to get 13, regroup 1 ten, and then add 3+3+1=7 tens.
Answer: 38+35=73.

Textbook page 43 · solved item 10

NCERT Class 5 Maths Chapter 4, solved question 10 — Question from the current NCERT textbook

Find the sum: 5+89.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add 5 to the 9 ones: 14 ones are 1 ten and 4 ones, making 94.
Answer: 5+89=94.

Textbook page 43 · solved item 11

NCERT Class 5 Maths Chapter 4, solved question 11 — Question from the current NCERT textbook

Find the sum: 76+28.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add the ones to get 14, then add 7+2+1=10 tens.
Answer: 76+28=104.

Textbook page 43 · solved item 12

NCERT Class 5 Maths Chapter 4, solved question 12 — Question from the current NCERT textbook

Find the sum: 69+20.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Adding 20 increases the tens by 2 while the 9 ones stay unchanged.
Answer: 69+20=89.

Detailed worked answers

Textbook page 44

Textbook page 44 · solved item 13

NCERT Class 5 Maths Chapter 4, solved question 13 — Question from the current NCERT textbook

Fill both blanks in relationship (a).

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Step 1: Addition joins two parts to make a total; subtraction removes one part from that total.
Step 2: Since 46+21=67, subtracting either part from 67 leaves the other part.
Answer: 67-21=46 and 67-46=21.

Textbook page 44 · solved item 14

NCERT Class 5 Maths Chapter 4, solved question 14 — Question from the current NCERT textbook

Fill both blanks in relationship (b).

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Step 1: Addition joins two parts to make a total; subtraction removes one part from that total.
Step 2: Since 198-98=100, adding the removed part back gives 198.
Answer: 100+98=198 and 198-100=98.

Textbook page 44 · solved item 15

NCERT Class 5 Maths Chapter 4, solved question 15 — Question from the current NCERT textbook

Fill both blanks in relationship (c).

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Step 1: Addition joins two parts to make a total; subtraction removes one part from that total.
Step 2: Since 189+98=287, subtracting one part from 287 leaves the other.
Answer: 287-98=189 and 287-189=98.

Textbook page 44 · solved item 16

NCERT Class 5 Maths Chapter 4, solved question 16 — Question from the current NCERT textbook

Fill both blanks in relationship (d).

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Step 1: Addition joins two parts to make a total; subtraction removes one part from that total.
Step 2: Since 872-672=200, adding 672 back gives 872.
Answer: 200+672=872 and 872-200=672.

Textbook page 44 · solved item 17

NCERT Class 5 Maths Chapter 4, solved question 17 — Question from the current NCERT textbook

Write the related addition and subtraction sentences for (a): 78 + 164 = 242.

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Step 1: Identify the whole and the two parts in the given fact.
Step 2: Subtract either part from the whole to find the other part; for a subtraction fact, add the difference and removed part to rebuild the whole.
Answer: 242-78=164 and 242-164=78.

Textbook page 44 · solved item 18

NCERT Class 5 Maths Chapter 4, solved question 18 — Question from the current NCERT textbook

Write the related addition and subtraction sentences for (b): 462 + 839 = 1,301.

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Step 1: Identify the whole and the two parts in the given fact.
Step 2: Subtract either part from the whole to find the other part; for a subtraction fact, add the difference and removed part to rebuild the whole.
Answer: 1,301-462=839 and 1,301-839=462.

Textbook page 44 · solved item 19

NCERT Class 5 Maths Chapter 4, solved question 19 — Question from the current NCERT textbook

Write the related addition and subtraction sentences for (c): 921 - 137 = 784.

Show detailed solution

Step 1: Identify the whole and the two parts in the given fact.
Step 2: Subtract either part from the whole to find the other part; for a subtraction fact, add the difference and removed part to rebuild the whole.
Answer: 784+137=921 and 921-784=137.

Textbook page 44 · solved item 20

NCERT Class 5 Maths Chapter 4, solved question 20 — Question from the current NCERT textbook

Write the related addition and subtraction sentences for (d): 824 - 234 = 590.

Show detailed solution

Step 1: Identify the whole and the two parts in the given fact.
Step 2: Subtract either part from the whole to find the other part; for a subtraction fact, add the difference and removed part to rebuild the whole.
Answer: 590+234=824 and 824-590=234.

Textbook page 44 · solved item 21

NCERT Class 5 Maths Chapter 4, solved question 21 — Question from the current NCERT textbook

A minibus had 18 litres of fuel and shows 65 litres after refuelling. How much fuel was added?

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Step 1: Subtract the fuel already present from the final amount: 65-18.
Step 2: Regroup 65 as 5 tens and 15 ones. Then 15-8=7 and 5-1=4.
Step 3: Check by adding: 18+47=65.
Answer: 47 litres of fuel were added.

Detailed worked answers

Textbook page 45

Textbook page 45 · solved item 22

NCERT Class 5 Maths Chapter 4, solved question 22 — Question from the current NCERT textbook

What is the difference between 82 and 37?

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Step 1: Line up equal place values before subtracting.
Step 2: Regroup 82 as 7 tens and 12 ones; 12-7=5 and 7-3=4. Check that 37+45=82.
Answer: 82-37=45.

Textbook page 45 · solved item 23

NCERT Class 5 Maths Chapter 4, solved question 23 — Question from the current NCERT textbook

Subtract: 57-11.

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Step 1: Line up equal place values before subtracting.
Step 2: Subtract 1 one and then 1 ten.
Answer: 57-11=46.

Textbook page 45 · solved item 24

NCERT Class 5 Maths Chapter 4, solved question 24 — Question from the current NCERT textbook

Subtract: 23-19.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup 23 as 1 ten and 13 ones; 13-9=4 and 1-1=0.
Answer: 23-19=4.

Textbook page 45 · solved item 25

NCERT Class 5 Maths Chapter 4, solved question 25 — Question from the current NCERT textbook

Subtract: 49-21.

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Step 1: Line up equal place values before subtracting.
Step 2: Subtract 1 one to get 8 ones and 2 tens to get 2 tens.
Answer: 49-21=28.

Textbook page 45 · solved item 26

NCERT Class 5 Maths Chapter 4, solved question 26 — Question from the current NCERT textbook

Subtract: 56-18.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup 56 as 4 tens and 16 ones; 16-8=8 and 4-1=3.
Answer: 56-18=38.

Textbook page 45 · solved item 27

NCERT Class 5 Maths Chapter 4, solved question 27 — Question from the current NCERT textbook

Subtract: 93-35.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup 93 as 8 tens and 13 ones; 13-5=8 and 8-3=5.
Answer: 93-35=58.

Textbook page 45 · solved item 28

NCERT Class 5 Maths Chapter 4, solved question 28 — Question from the current NCERT textbook

Subtract: 84-23.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Subtract 3 ones from 4 and 2 tens from 8.
Answer: 84-23=61.

Textbook page 45 · solved item 29

NCERT Class 5 Maths Chapter 4, solved question 29 — Question from the current NCERT textbook

Subtract: 70-43.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup 70 as 6 tens and 10 ones; 10-3=7 and 6-4=2.
Answer: 70-43=27.

Textbook page 45 · solved item 30

NCERT Class 5 Maths Chapter 4, solved question 30 — Question from the current NCERT textbook

Subtract: 65-47.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup 65 as 5 tens and 15 ones; 15-7=8 and 5-4=1.
Answer: 65-47=18.

Textbook page 45 · solved item 31

NCERT Class 5 Maths Chapter 4, solved question 31 — Question from the current NCERT textbook

State whether the displayed sums of 2 consecutive numbers are even or odd, and explain.

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Step 1: Check all four sums in the matching green box.
Step 2: One number is even and the next is odd. An even number plus an odd number is odd.
Answer: The sums are odd.

Textbook page 45 · solved item 32

NCERT Class 5 Maths Chapter 4, solved question 32 — Question from the current NCERT textbook

State whether the displayed sums of 3 consecutive numbers are even or odd, and explain.

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Step 1: Check all four sums in the matching green box.
Step 2: Each new sum is 3 more than the last. Adding an odd number changes even to odd and odd to even.
Answer: The sums are alternately even and odd.

Textbook page 45 · solved item 33

NCERT Class 5 Maths Chapter 4, solved question 33 — Question from the current NCERT textbook

State whether the displayed sums of 4 consecutive numbers are even or odd, and explain.

Show detailed solution

Step 1: Check all four sums in the matching green box.
Step 2: Every group has two even and two odd numbers. The two odd numbers make an even sum, so the total is even.
Answer: The sums are even.

Textbook page 45 · solved item 34

NCERT Class 5 Maths Chapter 4, solved question 34 — Question from the current NCERT textbook

What is the difference between successive displayed sums of 2 consecutive numbers?

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Step 1: Read the sums in order: 3, 5, 7, 9.
Step 2: Subtract each sum from the next. Every difference is 2.
Answer: The difference stays the same throughout and is 2.

Textbook page 45 · solved item 35

NCERT Class 5 Maths Chapter 4, solved question 35 — Question from the current NCERT textbook

What is the difference between successive displayed sums of 3 consecutive numbers?

Show detailed solution

Step 1: Read the sums in order: 6, 9, 12, 15.
Step 2: Subtract each sum from the next. Every difference is 3.
Answer: The difference stays the same throughout and is 3.

Textbook page 45 · solved item 36

NCERT Class 5 Maths Chapter 4, solved question 36 — Question from the current NCERT textbook

What is the difference between successive displayed sums of 4 consecutive numbers?

Show detailed solution

Step 1: Read the sums in order: 10, 14, 18, 22.
Step 2: Subtract each sum from the next. Every difference is 4.
Answer: The difference stays the same throughout and is 4.

Textbook page 45 · solved item 37

NCERT Class 5 Maths Chapter 4, solved question 37 — Question from the current NCERT textbook

What is the difference between successive sums of 5 consecutive numbers?

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Step 1: Moving to the next group removes the first number and adds a number 5 greater than it.
Step 2: The new sum therefore increases by 5.
Answer: The difference is 5.

Textbook page 45 · solved item 38

NCERT Class 5 Maths Chapter 4, solved question 38 — Question from the current NCERT textbook

What is the difference between successive sums of 6 consecutive numbers?

Show detailed solution

Step 1: Moving to the next group removes the first number and adds a number 6 greater than it.
Step 2: The new sum therefore increases by 6.
Answer: The difference is 6.

Detailed worked answers

Textbook page 46

Textbook page 46 · solved item 39

NCERT Class 5 Maths Chapter 4, solved question 39 — Question from the current NCERT textbook

Find 67+68+69 without adding every number one by one.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: 68 is the middle number, so the total is three groups of 68: 68+68+68=204.
Answer: 67+68+69=204.

Textbook page 46 · solved item 40

NCERT Class 5 Maths Chapter 4, solved question 40 — Question from the current NCERT textbook

Find 24+25+26+27 without adding every number one by one.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Pair the ends: 24+27=51 and 25+26=51; then 51+51=102.
Answer: 24+25+26+27=102.

Textbook page 46 · solved item 41

NCERT Class 5 Maths Chapter 4, solved question 41 — Question from the current NCERT textbook

Find 48+49+50+51+52 without adding every number one by one.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: 50 is the middle number, so five balanced numbers total 5\times50=250.
Answer: 48+49+50+51+52=250.

Textbook page 46 · solved item 42

NCERT Class 5 Maths Chapter 4, solved question 42 — Question from the current NCERT textbook

Find 237+238+239+240+241+242 without adding every number one by one.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Pair the ends. Each pair totals 479, and 479+479+479=1,437.
Answer: 237+238+239+240+241+242=1,437.

Textbook page 46 · solved item 43

NCERT Class 5 Maths Chapter 4, solved question 43 — Question from the current NCERT textbook

A point on the North-South Corridor was 1,855 km from Srinagar and 1,862 km from Kanniyakumari. What was the corridor's total length?

Show detailed solution

Step 1: The two distances meet at the same point, so add them: 1,855+1,862.
Step 2: Add by place value: ones give 7, tens give 11 tens, hundreds give 17 hundreds after regrouping, and thousands give 3.
Step 3: Check the size: two distances a little under 1,900 km should total a little under 3,800 km.
Answer: The North-South Corridor was 3,717 km long in 2019.

Detailed worked answers

Textbook page 47

Textbook page 47 · solved item 44

NCERT Class 5 Maths Chapter 4, solved question 44 — Question from the current NCERT textbook

Mahesh spends ₹21,880 on fuel and tolls and ₹38,900 on other expenses. How much does he spend in total?

Show detailed solution

Step 1: Add the two amounts: 21,880+38,900.
Step 2: Add by place value, regrouping 10 hundreds as 1 thousand and 10 thousands as 1 ten-thousand.
Step 3: The sum is 60,780, which is sensible because ₹22,000 and ₹39,000 are about ₹61,000.
Answer: Mahesh spends ₹60,780 in total.

Detailed worked answers

Textbook page 48

Textbook page 48 · solved item 45

NCERT Class 5 Maths Chapter 4, solved question 45 — Question from the current NCERT textbook

Find the sum: 238+367.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: The ones make 15, the tens make 10 after regrouping, and the hundreds make 6.
Answer: 238+367=605.

Textbook page 48 · solved item 46

NCERT Class 5 Maths Chapter 4, solved question 46 — Question from the current NCERT textbook

Find the sum: 1,234+12,345.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add each place from ones to ten-thousands; no place is skipped.
Answer: 1,234+12,345=13,579.

Textbook page 48 · solved item 47

NCERT Class 5 Maths Chapter 4, solved question 47 — Question from the current NCERT textbook

Find the sum: 12+123.

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Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Write 12 under the tens and ones of 123, then add each place.
Answer: 12+123=135.

Textbook page 48 · solved item 48

NCERT Class 5 Maths Chapter 4, solved question 48 — Question from the current NCERT textbook

Find the sum: 46,120+12,890.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: The ones are 0; the tens make 11 tens, and regrouping continues into the thousands.
Answer: 46,120+12,890=59,010.

Textbook page 48 · solved item 49

NCERT Class 5 Maths Chapter 4, solved question 49 — Question from the current NCERT textbook

Find the sum: 878+8,789.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Place 878 under the last three digits of 8,789 and regroup from ones through hundreds.
Answer: 878+8,789=9,667.

Textbook page 48 · solved item 50

NCERT Class 5 Maths Chapter 4, solved question 50 — Question from the current NCERT textbook

Find the sum: 1,749+17,490.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Align the 1,749 with the ones place of 17,490 and add from right to left.
Answer: 1,749+17,490=19,239.

Textbook page 48 · solved item 51

NCERT Class 5 Maths Chapter 4, solved question 51 — Question from the current NCERT textbook

Find the total distance of the Delhi-Mumbai-Goa-Hyderabad-Puri road trip shown on the map.

Show detailed solution

Step 1: Read the four marked distances: 1,600 km, 590 km, 670 km, and 1,055 km.
Step 2: Add in friendly groups: 1,600+590=2,190 and 670+1,055=1,725.
Step 3: Add the two subtotals: 2,190+1,725=3,915.
Answer: The total road-trip distance is 3,915 km.

Textbook page 48 · solved item 52

NCERT Class 5 Maths Chapter 4, solved question 52 — Question from the current NCERT textbook

Which two listed numbers have a sum closest to 10,000?

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Step 1: Add likely pairs and compare each sum with the target.
Step 2: Their sum is 10,045, only 45 away from 10,000.
Answer: Choose 5,205 and 4,840.

Textbook page 48 · solved item 53

NCERT Class 5 Maths Chapter 4, solved question 53 — Question from the current NCERT textbook

Which two listed numbers have a sum closest to 15,000?

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Step 1: Add likely pairs and compare each sum with the target.
Step 2: Their sum is 14,675, which is 325 away from 15,000.
Answer: Choose 6,220 and 8,455.

Textbook page 48 · solved item 54

NCERT Class 5 Maths Chapter 4, solved question 54 — Question from the current NCERT textbook

Which two listed numbers have a sum closest to 13,000?

Show detailed solution

Step 1: Add likely pairs and compare each sum with the target.
Step 2: Their sum is 13,295, which is 295 away from 13,000 and closer than the other pair sums.
Answer: Choose 8,455 and 4,840.

Textbook page 48 · solved item 55

NCERT Class 5 Maths Chapter 4, solved question 55 — Question from the current NCERT textbook

Which two listed numbers have a sum closest to 16,000?

Show detailed solution

Step 1: Add likely pairs and compare each sum with the target.
Step 2: Their sum is 15,550, only 450 away from 16,000.
Answer: Choose 7,095 and 8,455.

Detailed worked answers

Textbook page 49

Textbook page 49 · solved item 56

NCERT Class 5 Maths Chapter 4, solved question 56 — Question from the current NCERT textbook

A ship travels 1,083 km from Mumbai to Cochin on a 2,700 km route to Chennai. How much farther must it travel?

Show detailed solution

Step 1: Subtract the completed part from the full route: 2,700-1,083.
Step 2: Regroup across the zeroes. The ones give 7, tens give 1, hundreds give 6, and thousands give 1.
Step 3: Check by addition: 1,083+1,617=2,700.
Answer: The ship must travel 1,617 km more.

Detailed worked answers

Textbook page 50

Textbook page 50 · solved item 57

NCERT Class 5 Maths Chapter 4, solved question 57 — Question from the current NCERT textbook

How much longer is the 15,150 km Talon-Sagres route than the 10,228 km Cairo-Cape Town highway?

Show detailed solution

Step 1: Find the difference: 15,150-10,228.
Step 2: Regroup where needed and subtract from ones through ten-thousands.
Step 3: Check by adding the difference back: 10,228+4,922=15,150.
Answer: The Talon-Sagres route is 4,922 km longer.

Textbook page 50 · solved item 58

NCERT Class 5 Maths Chapter 4, solved question 58 — Question from the current NCERT textbook

Subtract: 4,578-2,222.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Subtract each place directly: 8-2, 7-2, 5-2, and 4-2.
Answer: 4,578-2,222=2,356.

Textbook page 50 · solved item 59

NCERT Class 5 Maths Chapter 4, solved question 59 — Question from the current NCERT textbook

Subtract: 15,324-11,780.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup in the tens and hundreds places, then continue to the thousands.
Answer: 15,324-11,780=3,544.

Textbook page 50 · solved item 60

NCERT Class 5 Maths Chapter 4, solved question 60 — Question from the current NCERT textbook

Subtract: 5,423-423.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: The last three digits cancel exactly, leaving 5 thousands.
Answer: 5,423-423=5,000.

Textbook page 50 · solved item 61

NCERT Class 5 Maths Chapter 4, solved question 61 — Question from the current NCERT textbook

Subtract: 123-12.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Align 12 under the tens and ones before subtracting.
Answer: 123-12=111.

Textbook page 50 · solved item 62

NCERT Class 5 Maths Chapter 4, solved question 62 — Question from the current NCERT textbook

Subtract: 77,777-777.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Align 777 under the final three digits; those three places cancel.
Answer: 77,777-777=77,000.

Textbook page 50 · solved item 63

NCERT Class 5 Maths Chapter 4, solved question 63 — Question from the current NCERT textbook

Subtract: 826-752.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Regroup 826 as 7 hundreds, 11 tens, and 16 ones before subtracting.
Answer: 826-752=74.

Detailed worked answers

Textbook page 51

Textbook page 51 · solved item 64

NCERT Class 5 Maths Chapter 4, solved question 64 — Question from the current NCERT textbook

Mary starts with ₹12,540, spends ₹3,275, receives ₹4,900, then spends ₹2,645 and ₹1,275. How much is left?

Show detailed solution

Step 1: After the first expense, she has 12,540-3,275=9,265.
Step 2: Add the gift: 9,265+4,900=14,165.
Step 3: After the ticket she has 14,165-2,645=11,520, and after souvenirs she has 11,520-1,275=10,245.
Answer: Mary has ₹10,245 left.

Textbook page 51 · solved item 65

NCERT Class 5 Maths Chapter 4, solved question 65 — Question from the current NCERT textbook

Estimate whether ₹70,500 is enough for purchases costing ₹39,785, ₹9,545, and ₹19,548.

Show detailed solution

Step 1: Round the costs to easy nearby amounts: about ₹40,000, ₹10,000, and ₹20,000.
Step 2: Their estimated total is about ₹70,000.
Answer: ₹70,500 should be enough, but only by a small amount. We should calculate exactly to check.

Textbook page 51 · solved item 66

NCERT Class 5 Maths Chapter 4, solved question 66 — Question from the current NCERT textbook

Check exactly whether the school council's ₹70,500 is enough for all three purchases.

Show detailed solution

Step 1: Add the purchases: 39,785+9,545=49,330.
Step 2: Add sports equipment: 49,330+19,548=68,878.
Step 3: Compare with the amount raised: 70,500-68,878=1,622.
Answer: Yes. The council has ₹1,622 left.

Textbook page 51 · solved item 67

NCERT Class 5 Maths Chapter 4, solved question 67 — Question from the current NCERT textbook

What total weight is loaded when a truck carries 3,675 kg of cement and 2,850 kg of steel?

Show detailed solution

Step 1: Add the two loads: 3,675+2,850.
Step 2: Add by place value and regroup to get 6,525.
Answer: The truck is carrying 6,525 kg.

Textbook page 51 · solved item 68

NCERT Class 5 Maths Chapter 4, solved question 68 — Question from the current NCERT textbook

How much more can the 8,250 kg truck carry after 6,525 kg has been loaded?

Show detailed solution

Step 1: Subtract the current load from the capacity: 8,250-6,525.
Step 2: Regroup where needed and subtract to get 1,725.
Answer: The truck can carry 1,725 kg more.

Textbook page 51 · solved item 69

NCERT Class 5 Maths Chapter 4, solved question 69 — Question from the current NCERT textbook

Fill the blank: 32 + ___ = 100.

Show detailed solution

Step 1: Count from 32 to 100 or subtract 100-32.
Step 2: From 32 to 40 is 8, and from 40 to 100 is 60; 8+60=68.
Answer: 32+68=100, so the missing number is 68.

Detailed worked answers

Textbook page 52

Textbook page 52 · solved item 70

NCERT Class 5 Maths Chapter 4, solved question 70 — Question from the current NCERT textbook

Use Piku's method to fill the blank: 59 + ___ = 100.

Show detailed solution

Step 1: First reach 99. The number needed is 40 because 59+40=99.
Step 2: Add 1 more to reach 100, so the full missing number is 40+1=41.
Answer: 59+41=100.

Textbook page 52 · solved item 71

NCERT Class 5 Maths Chapter 4, solved question 71 — Question from the current NCERT textbook

Fill the blank: 877 + ___ = 1,000.

Show detailed solution

Step 1: Use Piku's idea: first find the amount needed to reach the number made entirely of 9s just before the target.
Step 2: 877+122=999, then one more makes 1,000.
Answer: The missing number is 123.

Textbook page 52 · solved item 72

NCERT Class 5 Maths Chapter 4, solved question 72 — Question from the current NCERT textbook

Fill the blank: 666 + ___ = 1,000.

Show detailed solution

Step 1: Use Piku's idea: first find the amount needed to reach the number made entirely of 9s just before the target.
Step 2: 666+333=999, then one more makes 1,000.
Answer: The missing number is 334.

Textbook page 52 · solved item 73

NCERT Class 5 Maths Chapter 4, solved question 73 — Question from the current NCERT textbook

Fill the blank: 4,103 + ___ = 10,000.

Show detailed solution

Step 1: Use Piku's idea: first find the amount needed to reach the number made entirely of 9s just before the target.
Step 2: 4,103+5,896=9,999, then one more makes 10,000.
Answer: The missing number is 5,897.

Textbook page 52 · solved item 74

NCERT Class 5 Maths Chapter 4, solved question 74 — Question from the current NCERT textbook

Fill the blank: 5,555 + ___ = 10,000.

Show detailed solution

Step 1: Use Piku's idea: first find the amount needed to reach the number made entirely of 9s just before the target.
Step 2: 5,555+4,444=9,999, then one more makes 10,000.
Answer: The missing number is 4,445.

Textbook page 52 · solved item 75

NCERT Class 5 Maths Chapter 4, solved question 75 — Question from the current NCERT textbook

Does Piku's missing-addend method work when the units digit is 0? What other method can be used?

Show detailed solution

Step 1: Yes. For example, 60+39=99, and one more gives 60+40=100.
Step 2: Another method is to count up to the next ten and then to the target, or subtract the starting number from the target.
Answer: The method still works for a units digit of 0; counting up and subtraction also work.

Textbook page 52 · solved item 76

NCERT Class 5 Maths Chapter 4, solved question 76 — Question from the current NCERT textbook

Fill the blank: 180 + ___ = 1,000.

Show detailed solution

Step 1: Find how far the starting number is from 1,000.
Step 2: Check by addition: 180+820=1,000.
Answer: The missing number is 820.

Textbook page 52 · solved item 77

NCERT Class 5 Maths Chapter 4, solved question 77 — Question from the current NCERT textbook

Fill the blank: 760 + ___ = 1,000.

Show detailed solution

Step 1: Find how far the starting number is from 1,000.
Step 2: Check by addition: 760+240=1,000.
Answer: The missing number is 240.

Textbook page 52 · solved item 78

NCERT Class 5 Maths Chapter 4, solved question 78 — Question from the current NCERT textbook

Fill the blank: 400 + ___ = 1,000.

Show detailed solution

Step 1: Find how far the starting number is from 1,000.
Step 2: Check by addition: 400+600=1,000.
Answer: The missing number is 600.

Textbook page 52 · solved item 79

NCERT Class 5 Maths Chapter 4, solved question 79 — Question from the current NCERT textbook

Subtract: 67-9.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Add 1 to 67 to get 68, then subtract 10: 68-10=58.
Answer: 67-9=58.

Textbook page 52 · solved item 80

NCERT Class 5 Maths Chapter 4, solved question 80 — Question from the current NCERT textbook

Subtract: 83-9.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Add 1 to 83 to get 84, then subtract 10: 84-10=74.
Answer: 83-9=74.

Textbook page 52 · solved item 81

NCERT Class 5 Maths Chapter 4, solved question 81 — Question from the current NCERT textbook

Subtract: 144-9.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Add 1 to 144 to get 145, then subtract 10: 145-10=135.
Answer: 144-9=135.

Textbook page 52 · solved item 82

NCERT Class 5 Maths Chapter 4, solved question 82 — Question from the current NCERT textbook

Subtract: 187-99.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Add 1 to 187 to get 188, then subtract 100: 188-100=88.
Answer: 187-99=88.

Textbook page 52 · solved item 83

NCERT Class 5 Maths Chapter 4, solved question 83 — Question from the current NCERT textbook

Subtract: 247-99.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Add 1 to 247 to get 248, then subtract 100: 248-100=148.
Answer: 247-99=148.

Textbook page 52 · solved item 84

NCERT Class 5 Maths Chapter 4, solved question 84 — Question from the current NCERT textbook

Subtract: 763-99.

Show detailed solution

Step 1: Line up equal place values before subtracting.
Step 2: Add 1 to 763 to get 764, then subtract 100: 764-100=664.
Answer: 763-99=664.

Textbook page 52 · solved item 85

NCERT Class 5 Maths Chapter 4, solved question 85 — Question from the current NCERT textbook

Fill the blank: 32 - ___ = 9.

Show detailed solution

Step 1: The missing number is the part removed from the starting number.
Step 2: Subtract the desired answer from the starting number: 32-9=23.
Answer: The missing number is 23.

Textbook page 52 · solved item 86

NCERT Class 5 Maths Chapter 4, solved question 86 — Question from the current NCERT textbook

Fill the blank: 56 - ___ = 9.

Show detailed solution

Step 1: The missing number is the part removed from the starting number.
Step 2: Subtract the desired answer from the starting number: 56-9=47.
Answer: The missing number is 47.

Textbook page 52 · solved item 87

NCERT Class 5 Maths Chapter 4, solved question 87 — Question from the current NCERT textbook

Fill the blank: 877 - ___ = 99.

Show detailed solution

Step 1: The missing number is the part removed from the starting number.
Step 2: Subtract the desired answer from the starting number: 877-99=778.
Answer: The missing number is 778.

Textbook page 52 · solved item 88

NCERT Class 5 Maths Chapter 4, solved question 88 — Question from the current NCERT textbook

Fill the blank: 666 - ___ = 99.

Show detailed solution

Step 1: The missing number is the part removed from the starting number.
Step 2: Subtract the desired answer from the starting number: 666-99=567.
Answer: The missing number is 567.

Detailed worked answers

Textbook page 53

Textbook page 53 · solved item 89

NCERT Class 5 Maths Chapter 4, solved question 89 — Question from the current NCERT textbook

List all palindrome numbers between 100 and 200.

Show detailed solution

Step 1: A palindrome must read exactly the same from both ends.
Step 2: For a three-digit palindrome beginning with 1, the last digit must also be 1. Let the middle digit run from 0 to 9.
Answer: 101, 111, 121, 131, 141, 151, 161, 171, 181, 191.

Textbook page 53 · solved item 90

NCERT Class 5 Maths Chapter 4, solved question 90 — Question from the current NCERT textbook

List all palindrome numbers between 900 and 1,200.

Show detailed solution

Step 1: A palindrome must read exactly the same from both ends.
Step 2: List the three-digit palindromes beginning and ending in 9, then check four-digit numbers up to 1,200.
Answer: 909, 919, 929, 939, 949, 959, 969, 979, 989, 999, 1,001, 1,111.

Textbook page 53 · solved item 91

NCERT Class 5 Maths Chapter 4, solved question 91 — Question from the current NCERT textbook

List all palindrome numbers between 25,000 and 27,000.

Show detailed solution

Step 1: A palindrome must read exactly the same from both ends.
Step 2: A five-digit palindrome reads 2, then 5 or 6, a middle digit, and then those first two digits in reverse.
Answer: 25,052, 25,152, 25,252, 25,352, 25,452, 25,552, 25,652, 25,752, 25,852, 25,952, 26,062, 26,162, 26,262, 26,362, 26,462, 26,562, 26,662, 26,762, 26,862, 26,962.

Textbook page 53 · solved item 92

NCERT Class 5 Maths Chapter 4, solved question 92 — Question from the current NCERT textbook

Fill the first 3 by 3 grid so every row and column increases.

Show detailed solution

Step 1: Put the smallest numbers at the top-left and move to larger numbers across each row.
Step 2: Use the rows 1, 2, 3; then 4, 5, 6; then 7, 8, 9. Every column also increases from top to bottom.
Answer: One valid grid is \begin{matrix}1&2&3\\4&5&6\\7&8&9\end{matrix}.

Textbook page 53 · solved item 93

NCERT Class 5 Maths Chapter 4, solved question 93 — Question from the current NCERT textbook

Fill the second 3 by 3 grid so every row and column decreases.

Show detailed solution

Step 1: Put the largest numbers at the top-left and move to smaller numbers across each row.
Step 2: Use the rows 9, 8, 7; then 6, 5, 4; then 3, 2, 1. Every column also decreases.
Answer: One valid grid is \begin{matrix}9&8&7\\6&5&4\\3&2&1\end{matrix}.

Textbook page 53 · solved item 94

NCERT Class 5 Maths Chapter 4, solved question 94 — Question from the current NCERT textbook

Fill the left mixed inc/dec grid using 1 to 9 once each.

Show detailed solution

Step 1: Read the direction labels: Rows decrease and columns increase.
Step 2: Place the numbers, then check every row and column. Each row moves down in value from left to right, while each column grows from top to bottom.
Answer: One valid grid is \begin{matrix}3&2&1\\6&5&4\\9&8&7\end{matrix}.

Textbook page 53 · solved item 95

NCERT Class 5 Maths Chapter 4, solved question 95 — Question from the current NCERT textbook

Fill the middle mixed inc/dec grid using 1 to 9 once each.

Show detailed solution

Step 1: Read the direction labels: The first two rows and columns decrease; the last row and column increase.
Step 2: Place the numbers, then check every row and column. Check each outside inc or dec label: 9, 7, 3 and 8, 6, 4 decrease, while 1, 2, 5 increases.
Answer: One valid grid is \begin{matrix}9&8&1\\7&6&2\\3&4&5\end{matrix}.

Textbook page 53 · solved item 96

NCERT Class 5 Maths Chapter 4, solved question 96 — Question from the current NCERT textbook

Fill the right mixed inc/dec grid using 1 to 9 once each.

Show detailed solution

Step 1: Read the direction labels: The first two rows and first column increase; the last row and last two columns decrease.
Step 2: Place the numbers, then check every row and column. The rows 1,8,9 and 2,6,7 increase; 5,4,3 decreases. The columns match their labels too.
Answer: One valid grid is \begin{matrix}1&8&9\\2&6&7\\5&4&3\end{matrix}.

Detailed worked answers

Textbook page 54

Textbook page 54 · solved item 97

NCERT Class 5 Maths Chapter 4, solved question 97 — Question from the current NCERT textbook

Should (a) 297 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 7, so it cannot be split into pairs with none left over.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 98

NCERT Class 5 Maths Chapter 4, solved question 98 — Question from the current NCERT textbook

Should (b) 498 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 8, an even digit.
Answer: It is even, so circle it.

Textbook page 54 · solved item 99

NCERT Class 5 Maths Chapter 4, solved question 99 — Question from the current NCERT textbook

Should (c) 724 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 4, an even digit.
Answer: It is even, so circle it.

Textbook page 54 · solved item 100

NCERT Class 5 Maths Chapter 4, solved question 100 — Question from the current NCERT textbook

Should (d) 100 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 0, an even digit.
Answer: It is even, so circle it.

Textbook page 54 · solved item 101

NCERT Class 5 Maths Chapter 4, solved question 101 — Question from the current NCERT textbook

Should (e) 199 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 9, so one is left unpaired.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 102

NCERT Class 5 Maths Chapter 4, solved question 102 — Question from the current NCERT textbook

Should (f) 789 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 9, an odd digit.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 103

NCERT Class 5 Maths Chapter 4, solved question 103 — Question from the current NCERT textbook

Should (g) 49 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 9, an odd digit.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 104

NCERT Class 5 Maths Chapter 4, solved question 104 — Question from the current NCERT textbook

Should (h) 6,893 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 3, an odd digit.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 105

NCERT Class 5 Maths Chapter 4, solved question 105 — Question from the current NCERT textbook

Should (i) 846 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 6, an even digit.
Answer: It is even, so circle it.

Textbook page 54 · solved item 106

NCERT Class 5 Maths Chapter 4, solved question 106 — Question from the current NCERT textbook

Should (j) 111 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 1, an odd digit.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 107

NCERT Class 5 Maths Chapter 4, solved question 107 — Question from the current NCERT textbook

Should (k) 222 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 2, an even digit.
Answer: It is even, so circle it.

Textbook page 54 · solved item 108

NCERT Class 5 Maths Chapter 4, solved question 108 — Question from the current NCERT textbook

Should (l) 1,023 be circled as an even number?

Show detailed solution

Step 1: Look only at the ones digit.
Step 2: Its ones digit is 3, an odd digit.
Answer: It is odd, so do not circle it.

Textbook page 54 · solved item 109

NCERT Class 5 Maths Chapter 4, solved question 109 — Question from the current NCERT textbook

Add 2 to the paired arrangement for 18. What changes and what stays the same?

Show detailed solution

Step 1: 18 has 9 complete pairs and no unpaired dot.
Step 2: Adding 2 makes one new pair, giving 20 with 10 complete pairs.
Answer: The number of pairs increases by 1, and the arrangement remains even with no unpaired dot.

Textbook page 54 · solved item 110

NCERT Class 5 Maths Chapter 4, solved question 110 — Question from the current NCERT textbook

Add 2 to the paired arrangement for 23. What changes and what stays the same?

Show detailed solution

Step 1: 23 has 11 complete pairs and 1 unpaired dot.
Step 2: Adding 2 makes one new pair, giving 25 with 12 pairs and still 1 unpaired dot.
Answer: The number of pairs increases by 1, and the number remains odd.

Textbook page 54 · solved item 111

NCERT Class 5 Maths Chapter 4, solved question 111 — Question from the current NCERT textbook

Choose five pairs of even numbers, add each pair, and describe the result.

Show detailed solution

Step 1: Examples are 2+4=6, 6+8=14, 10+12=22, 14+16=30, and 18+20=38.
Step 2: Every answer is even because each starting number is made of complete pairs, and joining them leaves complete pairs.
Answer: The sum of two even numbers is always even.

Textbook page 54 · solved item 112

NCERT Class 5 Maths Chapter 4, solved question 112 — Question from the current NCERT textbook

Choose five pairs of odd numbers, add each pair, and describe the result.

Show detailed solution

Step 1: Examples are 1+3=4, 5+7=12, 9+11=20, 13+15=28, and 17+19=36.
Step 2: The single unpaired dot from each odd number joins to make one more pair.
Answer: The sum of two odd numbers is always even.

Textbook page 54 · solved item 113

NCERT Class 5 Maths Chapter 4, solved question 113 — Question from the current NCERT textbook

Choose five odd-even pairs, add each pair, and describe the result.

Show detailed solution

Step 1: Examples are 1+2=3, 3+4=7, 5+6=11, 7+8=15, and 9+10=19.
Step 2: The even number has no unpaired dot, while the odd number has one, so one dot stays unpaired.
Answer: The sum of an odd number and an even number is always odd.

Textbook page 54 · solved item 114

NCERT Class 5 Maths Chapter 4, solved question 114 — Question from the current NCERT textbook

Jincy has eight ₹1 coins, nine ₹2 coins, and five ₹5 coins. Give one way to pay exactly ₹38.

Show detailed solution

Step 1: Use five ₹5 coins: 5\times₹5=₹25.
Step 2: Use six ₹2 coins: 6\times₹2=₹12, and one ₹1 coin. These are all within the available counts.
Step 3: Check: ₹25+₹12+₹1=₹38.
Answer: One possible combination is five ₹5 coins, six ₹2 coins, and one ₹1 coin.

Textbook page 54 · solved item 115

NCERT Class 5 Maths Chapter 4, solved question 115 — Question from the current NCERT textbook

Will Raghu's torch be ON or OFF after the 23rd press?

Show detailed solution

Step 1: The torch is ON after press 1, OFF after press 2, and this two-step pattern repeats.
Step 2: Odd-numbered presses turn it ON; even-numbered presses turn it OFF.
Step 3: 23 is odd.
Answer: The torch will be ON after the 23rd press.

Detailed worked answers

Textbook page 55

Textbook page 55 · solved item 116

NCERT Class 5 Maths Chapter 4, solved question 116 — Question from the current NCERT textbook

For which press numbers is the torch ON, and for which is it OFF?

Show detailed solution

Step 1: Starting from OFF, each press changes the state.
Step 2: Presses 1, 3, 5, and all other odd numbers leave it ON; presses 2, 4, 6, and all other even numbers leave it OFF.
Answer: The torch is ON after odd-numbered presses and OFF after even-numbered presses.

Textbook page 55 · solved item 117

NCERT Class 5 Maths Chapter 4, solved question 117 — Question from the current NCERT textbook

Which is the highest peak Priyanka climbed?

Show detailed solution

Step 1: Read the needed height or year from the table.
Step 2: Compare all heights in the table. The greatest height is 8,848 metres.
Answer: Mount Everest is the highest peak, at 8,848 metres.

Textbook page 55 · solved item 118

NCERT Class 5 Maths Chapter 4, solved question 118 — Question from the current NCERT textbook

What is the difference between the highest and lowest peaks in the table?

Show detailed solution

Step 1: Read the needed height or year from the table.
Step 2: The highest is 8,848 m and the lowest is 5,642 m. Subtract: 8,848-5,642=3,206.
Answer: The difference is 3,206 metres.

Textbook page 55 · solved item 119

NCERT Class 5 Maths Chapter 4, solved question 119 — Question from the current NCERT textbook

What is the difference between the heights of Mount Elbrus and Mount Kanchenjunga?

Show detailed solution

Step 1: Read the needed height or year from the table.
Step 2: Kanchenjunga is 8,586 m and Elbrus is 5,642 m. Subtract: 8,586-5,642=2,944.
Answer: The difference is 2,944 metres.

Textbook page 55 · solved item 120

NCERT Class 5 Maths Chapter 4, solved question 120 — Question from the current NCERT textbook

If Priyanka was 20 years old when she climbed Mount Everest in 2013, in which year was she born?

Show detailed solution

Step 1: Read the needed height or year from the table.
Step 2: Count back 20 years from 2013: 2013-20=1993.
Answer: She was born in 1993, assuming her birthday had already occurred by the summit date.

Detailed worked answers

Textbook page 56

Textbook page 56 · solved item 121

NCERT Class 5 Maths Chapter 4, solved question 121 — Question from the current NCERT textbook

Were the certificates sufficient for Chittoor, A.P., and by how many?

Show detailed solution

Step 1: Compare the certificates printed with the students who attended.
Step 2: More certificates were printed than needed. Subtract 18,225-18,104=121.
Answer: The certificates were sufficient, with 121 extra.

Textbook page 56 · solved item 122

NCERT Class 5 Maths Chapter 4, solved question 122 — Question from the current NCERT textbook

Were the certificates sufficient for Jaunpur, U.P., and by how many?

Show detailed solution

Step 1: Compare the certificates printed with the students who attended.
Step 2: More students attended than there were certificates. Subtract 19,265-19,043=222.
Answer: The certificates were insufficient; 222 more were needed.

Textbook page 56 · solved item 123

NCERT Class 5 Maths Chapter 4, solved question 123 — Question from the current NCERT textbook

Were the certificates sufficient for Raigad, Maharashtra, and by how many?

Show detailed solution

Step 1: Compare the certificates printed with the students who attended.
Step 2: More certificates were printed than needed. Subtract 20,863-19,974=889.
Answer: The certificates were sufficient, with 889 extra.

Textbook page 56 · solved item 124

NCERT Class 5 Maths Chapter 4, solved question 124 — Question from the current NCERT textbook

Find the sum: 2,009+7,388.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add by place value, regrouping 17 hundreds as 1 thousand and 7 hundreds.
Answer: 2,009+7,388=9,397.

Textbook page 56 · solved item 125

NCERT Class 5 Maths Chapter 4, solved question 125 — Question from the current NCERT textbook

Find the sum: 26,444+71,111.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Each place adds without regrouping: ones 5, tens 5, hundreds 5, thousands 7, ten-thousands 9.
Answer: 26,444+71,111=97,555.

Textbook page 56 · solved item 126

NCERT Class 5 Maths Chapter 4, solved question 126 — Question from the current NCERT textbook

Find the sum: 777+888.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Regroup in the ones, tens, and hundreds places.
Answer: 777+888=1,665.

Textbook page 56 · solved item 127

NCERT Class 5 Maths Chapter 4, solved question 127 — Question from the current NCERT textbook

Find the sum: 1,234+1,234.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Double each place from right to left.
Answer: 1,234+1,234=2,468.

Textbook page 56 · solved item 128

NCERT Class 5 Maths Chapter 4, solved question 128 — Question from the current NCERT textbook

Find the sum: 56+56,789.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Write 56 under the tens and ones of 56,789 before adding.
Answer: 56+56,789=56,845.

Textbook page 56 · solved item 129

NCERT Class 5 Maths Chapter 4, solved question 129 — Question from the current NCERT textbook

Find the sum: 777+77,777.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Align the three-digit number at the right and regroup through the thousands.
Answer: 777+77,777=78,554.

Textbook page 56 · solved item 130

NCERT Class 5 Maths Chapter 4, solved question 130 — Question from the current NCERT textbook

Add the next printed (f): 5,922+9,221.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add each place and regroup 11 thousands as 1 ten-thousand and 1 thousand.
Answer: 5,922+9,221=15,143.

Textbook page 56 · solved item 131

NCERT Class 5 Maths Chapter 4, solved question 131 — Question from the current NCERT textbook

Find the sum: 4,321+8,765.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Regroup from ones through thousands while keeping every place aligned.
Answer: 4,321+8,765=13,086.

Textbook page 56 · solved item 132

NCERT Class 5 Maths Chapter 4, solved question 132 — Question from the current NCERT textbook

Find the sum: 50,050+55,000.

Show detailed solution

Step 1: Line up the ones, tens, hundreds, and larger places correctly.
Step 2: Add the thousands and ten-thousands; the 50 in the final two places stays unchanged.
Answer: 50,050+55,000=105,050.

Textbook page 56 · solved item 133