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Reviewed source answers
Solution sheet 1
Source solution page 20

Think about various situations where we use numbers. List five different situations in which numbers are used. See what your classmates have listed, share, and discuss.
Show solution
Five different possible situations in which numbers are used - 1. Time 2. Calendar 3. Counting objects/Marks 4. Measurement of height & weight 5. Money There could many more. Section 3.1 Page No. 55

Section 3.1 · Page No. 55

What do you think these numbers mean?
Show solution
Refer page 56. Page No. 56

Refer page 56. · Page No. 56

1. Can the children rearrange themselves so that the children standing at the ends say ‘2’?
Show solution
No; There will be no one standing on the other side of the child standing at the end.

Refer page 56. · Page No. 56

2. Can we arrange the children in a line so that all would say only 0s?
Show solution
Yes; All the children in the line should be of same height.

Refer page 56. · Page No. 56

3. Can two children standing next to each other say the same number?
Show solution
Yes; Refer picture on page 55.

Page No. 56 · Ans. Yes; Refer picture on page 55.

4. There are 5 children in a group, all of different heights. Can they stand such that four of them say ‘1’ and the last one says ‘0’? Why or why not?
Show solution
Yes, they can, if they are standing in ascending order of height. [1]


Reviewed source answers
Solution sheet 2
Ans. Yes; Refer picture on page 55.

5. For this group of 5 children, is the sequence 1, 1, 1, 1, 1 possible?
Show solution
No; the tallest child at the end cannot say1.

Ans. Yes; Refer picture on page 55.

6. Is the sequence 0, 1, 2, 1, 0 possible? Why or why not?
Show solution
Yes, it is possible.

Source solution page 21

7. How would you rearrange the five children so that the maximum number of children say ‘2’?
Show solution
At the most only 2 children can say 2 as given is the following arrangement. Section 3.2 Page No. 57 Figure it out

Page No. 57 · Figure it out

1. Colour or mark the supercells in the table below. 6828 670 9435 3780 3708 7308 8000 5583 52
Show solution
6828 670 9435 3780 3708 7308 8000 5583 52 [2]


Reviewed source answers
Solution sheet 3
Source solution page 22

2. Fill the table below with only 4-digit numbers such that the supercells are exactly the coloured cells. 5346 1258 9635
Show solution
One of the ways could be-5346; 9636.Try more 5346 5347 1000 1258 1100 1200 1300 9635 9636

Source solution page 22

3. Fill the table below such that we get as many supercells as possible. Use numbers between 100 and 1000 without repetitions.
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110 100 150 130 280 200 230 210 270

Source solution page 22

4. Out of the 9 numbers, how many supercells are there in the table above? ___________
Show solution
5

Source solution page 22

5 Find out how many supercells are possible for different numbers of cells. Do you notice any pattern? What is the method to fill a given table to get the maximum number of supercells? Explore and share your strategy.
Show solution
For even number of cells say,2,4,6,… the number of supercells would be respectively, 2/2 =1,4/2 =2,6/2=3,… For odd number of cells , say 1,3,5,7,… the number of supercells would be respectively (1+1)/2= 1, (3+1)/2 = 2, (5+1)/2= 3,(7+1)/2 = 4,… To get the maximum number ofsupercells, we have to start by filling the first cell as super cell & then fill alternately.

Source solution page 22

6. Can you fill a supercell table without repeating numbers such that there are no supercells? Why or why not?
Show solution
No; the cell which is filled by the greatest number among the given numbers chosen, will become super cell irrespective of its position in the table.

Source solution page 22

7. Will the cell having the largest number in a table always be a supercell? Can the cell having the smallest number in a table be a supercell? Why or why not?
Show solution
Yes, the largest number in a table will always be a supercell. No, the smallest number in a table can never be a supercell as the number in all the adjacent cells will be greater than it.

Source solution page 22

8. Fill a table such that the cell having the second largest number is not a supercell.
Show solution
One of the ways could be- 1 2 3 4 5 6 7 9 8 [3]


Reviewed source answers
Solution sheet 4
Source solution page 23

9. Fill a table such that the cell having the second largest number is not a supercell but the second smallest number is a supercell. Is it possible?
Show solution
One of the ways is- 2 1 3 4 5 6 7 9 8 Second smallest number a super cell Second largest number 8 is not a supercell.

Source solution page 23

10. Make other variations of this puzzle and challenge your classmates.
Show solution
Some of these could be- Can you fill the table with 9 cells such that there are more than 5 super cells? Can you fill the table with 9 cells such that there are exactly 4 super cells? Page No. 58

Page No. 58

Complete Table 2 with 5-digit numbers whose digits are ‘1’, ‘0’, ‘6’, ‘3’, and ‘9’ in some order. Only a coloured cell should have a number greater than all its neighbours.
Show solution
Table 2 (One of the ways) – 96,310 96,301 36,109 39,160 96,103 13,609 60,319 19,306 13,906 10,396 60,193 60,931 10,369 10,963 10,936 69,031

Source solution page 23

The biggest number in the table is ____________.
Show solution
The biggest number in the table is 96,310

Source solution page 23

The smallest even number in the table is ____________.
Show solution
The smallest even number in the table is 10,396

Source solution page 23

The smallest number greater than 50,000 in the table is ____________.
Show solution
The smallest number greater than 50,000 in the table is 60,193. Section 3.3 Page no.59

Section 3.3 · Page no.59

We are quite familiar with number lines now. Let’s see if we can place some numbers in their appropriate positions on the number line. Here are the numbers: 2180, 2754, 1500, 3600, 9950, 9590, 1050, 3050, 5030, 5300 and 8400.
Show solution
2180 1050 8400 9950 3600 5030 2754 1000 9000 8000 2000 3000 4000 5000 6000 10000 7000 1500 5300 9590 [4]


Reviewed source answers
Solution sheet 5
Source solution page 24

Identify the numbers marked on the number lines below, and label the remaining
Show solution
positions. (a). 2025 2030 1995 2000 2005 2010 2015 2035 1990 2020 (b). 10001 10000 9998 10002 9995 9996 9997 9993 9999 9994 (c). 15085 15077 15084 15078 15079 15080 15081 15082 15086 15083 (d). 91705 83705 90705 84705 85705 86705 87705 88705 92705 89705 Put a circle around the smallest number and a box around the largest number in each of the sequences above. Section 3.4 Page no. 60

Section 3.4 · Page no. 60

Find out how many numbers have two digits, three digits, four digits, and five digits: 1 Digit numbers 2 Digit numbers 3 Digit numbers 4 Digit numbers 5 Digit numbers 9
Show solution
1 Digit numbers 2 Digit numbers 3 Digit numbers 4 Digit numbers 5 Digit numbers 9 90 900 9,000 90,000 [5] Figure it out


Reviewed source answers
Solution sheet 6
Figure it out

1. Digit sum 14 a. Write other numbers whose digits add up to 14. b. What is the smallest number whose digit sum is 14? c. What is the largest 5-digit number whose digit sum is 14? d. How big a number can you form having the digit sum 14? Can you make an even bigger number?
Show solution
a. Some such numbers are:248, 653, 356, 815, 833, 12335, 23351. b. 59 c. 95000 d. 95, 9005, 900005, 90000005, 9000000005, 90000000000005 …

Source solution page 25

3. Calculate the digit sums of 3-digit numbers whose digits are consecutive (for example, 345). Do you see a pattern? Will this pattern continue?
Show solution
123 → 1+2+3 = 6 234 → 2+3+4 = 9 345 → 3+4+5 = 12 456 → 4+5+6 = 15 567 → 5+6+7 = 18 678 → 6+7+8 = 21 789 → 7+8+9 = 24 • Yes, there is a pattern, all the sums are multiples of 3. • No. Page no. 61

Page no. 61

Among the numbers 1–100, how many times will the digit ‘7’ occur? Among the numbers 1–1000, how many times will the digit ‘7’ occur?
Show solution
• 20 times. • 300 times. [6] Section 3.5 Page no. 61


Reviewed source answers
Solution sheet 7
Section 3.5 · Page no. 61

Write all possible 3-digit palindromes using these digits.
Show solution
Palindromes: 111, 121, 131 222, 212, 232 313, 323, 333 Explore Page no. 62

Page no. 61 · Page no. 62

Will reversing and adding numbers repeatedly, starting with a 2-digit number,
Show solution
always give a palindrome? Explore and find out.* Some of these are- 12 +21 33 47 +74 121 Try more Yes, it will always give a palindrome. Puzzle time

Source solution page 26

I am a 5-digit palindrome. I am an odd number. My ‘t’ digit is double of my ‘u’ digit. My ‘h’ digit is double of my ‘t’ digit. Who am I? _________________
Show solution
tth th h t u 1 2 4 2 1 Twelve thousand four hundred twenty one. Section 3.6 Page no. 63

Section 3.6 · Page no. 63

Carry out these same steps with a few 3-digit numbers. What number will start repeating?
Show solution
Take a 3- Digit number say, 321. 321 -123 198 981 -189 792 972 -279 693 963 -369 594 954 -459 495 954 -459 495 The number 495 starts repeating. Try for other 3-digit numbers. [7] Section 3.7 Page no. 64


Reviewed source answers
Solution sheet 8
Section 3.7 · Page no. 64

Try and find out all possible times on a 12-hour clock of each of these types.
Show solution
4:44 2:22 3:33 10:10 11:11 12:12 09:09 12:21 05:50 10:01 Think of some more!

Think of some more!

Find some other dates of this form from the past.
Show solution
20/04/2004, 20/06/2006, Try for yourself!

Think of some more!

Find all possible dates of this form from the past.
Show solution
01/02/2001, 02/02/2002, Think of some more!

Think of some more!

Will any year’s calendar repeat again after some years? Will all dates and days in a year match exactly with that of another year?
Show solution
Yes, The calendar repeats itself after 6 years if only one leap year is included in these 6 years. If 2 leap years are included, then it will repeat after 5 years. Page no. 64 Figure it out

Page no. 64 · Figure it out

1. Pratibha uses the digits ‘4’, ‘7’, ‘3’ and ‘2’, and makes the smallest and largest 4- digit numbers with them: 2347 and 7432. The difference between these two numbers is 7432 – 2347 = 5085. The sum of these two numbers is 9779. Choose 4– digits to make: a. the difference between the largest and smallest numbers greater than 5085. b. the difference between the largest and smallest numbers less than 5085. c. the sum of the largest and smallest numbers greater than 9779. d. the sum of the largest and smallest nu...
Show solution
Some of the possibilities are– a. 7431 – 1347 = 6084 b. 7433 – 3347 = 4086 c. 7433 + 3347 = 10780 d. 7431 + 1347 = 8778

Source solution page 27

2. What is the sum of the smallest and largest 5-digit palindrome? What is their difference?
Show solution
Smallest 5 digit palindrome = 10001 largest 5 digit palindrome = 99999 Sum = 10001 + 99999 = 110,000 Difference = 99999 – 10001 = 89,998 [8]


Reviewed source answers
Solution sheet 9
Source solution page 28

3. The time now is 10:01. How many minutes until the clock shows the next palindromic time? What about the one after that?
Show solution
Time Now → 10:01 Next palindrome time → 11:11 After 1 hr. 10 min = 70 min the clock will show next palindrome time. Next palindrome time = 12:21 which will occur after 2 hr. 20 min = 140 min from 10:01.

Source solution page 28

4. How many rounds does the number 5683 take to reach the Kaprekar constant?
Show solution
5683 8653 -3568 5085 8550 -5058 3492 9432 -2349 7083 8730 -3078 5652 6552 -2556 3996 9963 -3699 6264 6642 -2466 4176 7641 -1467 6174 1 2 3 4 5 6 7 8 It will take 8 rounds to reach the Kaprekar constant. Page no. 66 Section 3.8

Page no. 66 · Section 3.8

Can we make 1,000 using the numbers in the middle? Why not? What about 14,000, 15,000 and 16,000? Yes, it is possible. Explore how. What thousands cannot be made?
Show solution
No; the only number which is smaller than 1000 is 400 and 1000 is not a multiple of 400. 14000 = 1500 × 8 + 400 × 5 = 12000 + 2000 = 14000 15000 = 13000 + 400 × 5 = 13000 + 2000 = 15000 16000 = 1500 × 8 + 400 × 10 = 12000 + 4000 = 16000 Only one thousand (1000) cannot be made. Figure it out

Figure it out

1. Write an example for each of the below scenarios whenever possible. Could you find examples for all the cases? If not, think and discuss what could be the reason. Make other such questions and challenge your classmates.
Show solution
• 5 digit + 5 digit > 90,250 45,000 + 45,400 = 90,400 > 90,250 • 5 digit + 3 digit = 6 digit sum 99,999 + 999 = 100,998 • 4 digit + 4 digit = 6 digit sum Not possible as even the sum of the greatest 4 digit numbers will not give a six digit sum. (9999 + 9999 = 19,998) [9] • 5 digit + 5 digit = 6 digit sum 60,000 + 40,000 = 1,00,000 • 5 digit + 5 digit = 18,500 Not possible as smallest 5-digit number is 10,000. If both the numbers are 10,000 then the sum is 20,000, which is more than 18,500. • 5 digit – 5 digit < 56,503 80,000 – 50,000 < 56,503 < 56,503 • 5 digit – 3 digit = 4 digit difference 10,000 – 999 = 9001 • 5 digit – 4 digit = 4 digit difference 12,000 – 2,500 = 9,500 • 5 digit – 5 digit = 3 digit difference 50,999 – 50,000 = 999 • 5 digit – 5 digit = 91,500 Not possible as the difference of the greatest and the smallest 5 digit numbers, the maximum difference, can be 99,999 – 10,000 = 89,999 Some examples of other such questions are- 1. 5 digit + 5 digit = 7 digit sum 2. 4 digit + 4 digit = 2900 More such examples can be made.


Reviewed source answers
Solution sheet 10
Source solution page 29

2. Always, Sometimes, Never? Below are some statements. Think, explore and find out if each of the statement is ‘Always true’, ‘Only sometimes true’ or ‘Never true’. Why do you think so? Write your reasoning; discuss this with the class. a. 5-digit number + 5-digit number gives a 5-digit number b. 4-digit number + 2-digit number gives a 4-digit number c. 4-digit number + 2-digit number gives a 6-digit number d. 5-digit number – 5-digit number gives a 5-digit number e. 5-digit number – 2-digit number gives a 3-di...
Show solution
a. Only sometimes true. 20,000 + 80,000 = 1,00,000 not a 5 digit number b. Only sometimes true 9,999 + 99 = 10,098 not a 4 digit number c. Never true 9,999 + 99 = 10,098 On adding the greatest 4 digit and the greatest 2 digit numbers, we can reach only 5 digit number 10,098. So there is no possibility of getting a 6 digit number. d. Only sometimes true Ex. 12,000 – 10,000 = 2,000 5 digit – 5 digit = 4 digit e. Never true Ex. 10,000 – 99 = 9901 [10] Even if the greatest 2 digit numbers is subtracted from the smallest 5 digit number, 4 digit number will be obtained. Page no. 69 Section 3.10


Reviewed source answers
Solution sheet 11
Page no. 69 · Section 3.10

Make some more Collatz sequences like those above, starting with your favourite whole numbers. Do you always reach 1? Do you believe the conjecture of Collatz that all such sequences will eventually reach 1? Why or why not?
Show solution
a) 28, 14, 7, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1 b) 19, 58, 29, 88, 44, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1 Yes we always reach 1. The even numbers are halved and when we have an odd number we convert it into an even number by multiplying by 3 and adding 1 so that eventually it can be halved again. The smallest even number is 2 so we will reach 1 for sure.

Source solution page 30

3. Name some objects around you that are: a. a few thousand in number b. more than ten thousand in number
Show solution
A few thousands: car numbers, 4 digit pin More than ten thousands: Salary, Mobile numbers.

Source solution page 30

3. Roshan wants to buy milk and 3 types of fruit to make fruit custard for 5 people. He estimates the cost to be ₹ 100. Do you agree with him? Why or why not?
Show solution
Yes, it is possible with less quantity of serving and with purchase of 1-1-1 fruit of each type. However, it is not possible with costly fruits and more quantity of serving.

Source solution page 30

4. Estimate the distance between Gandhinagar (in Gujarat) to Kohima (in Nagaland).
Show solution
2500 kilometer

Source solution page 30

5. Sheetal is in Grade 6 and says she has spent around 13,000 hours in school till date. Do you agree with her? Why or why not?
Show solution
No, I do not agree with her. There are 6 school hours in a day and around 200 working days in a year. 𝟏𝟑,𝟎𝟎𝟎 𝟔×𝟐𝟎𝟎 = 10.8 years (Nursery, KG, 1,2,3,4,5,6) 8 years She is in school for 8 years, 13,000 hours is way too high.

Source solution page 30

7. Make some estimation questions and challenge your classmates!
Show solution
Some such are • How many students are there in your school? • How many hours does a person sleep in his lifetime on an average? (More such questions can be made) [11] Section 3.12 Page No. 72 Figure it Out


Reviewed source answers
Solution sheet 12
Page No. 72 · Figure it Out

1. There is only one supercell (number greater than all its neighbours) in this grid. If you exchange two digits of one of the numbers, there will be 4 supercells. Figure out which digits to swap. 16,200 39,344 29,765 23,609 62,871 45,306 19,381 50,319 38,408
Show solution
If I exchange the digits 1 and 6 in the number 62,871 then there will be 4 Super cells. 16,200 39,344 29,765 23,609 12,876 45,306 19,381 50,319 38,408

Source solution page 31

2. How many rounds does your year of birth take to reach the Kaprekar constant?
Show solution
Suppose the birth year is 1980, then, - 9810 -1089 8721 8721 -1278 7443 7443 -3447 3996 9963 -3699 6264 6642 -2466 4176 7641 -1467 6174 It takes 6 rounds. (Try now for your year of birth.)

Source solution page 31

3. We are the group of 5-digit numbers between 35,000 and 75,000 such that all of our digits are odd. Who is the largest number in our group? Who is the smallest number in our group? Who among us is the closest to 50,000?
Show solution
73,951 With repeating digit With non repeating digit Largest number → 73,999 Smallest number → 35,111 35,179 With repeating digit With non repeating digit Closest to 50000 51,111 51,379

Source solution page 31

6. Write one 5-digit number and two 3-digit numbers such that their sum is 18,670.
Show solution
18000 + 300 + 370 = 18670. Try for more. [12]


Reviewed source answers
Solution sheet 13
Source solution page 32

7. Choose a number between 210 and 390. Create a number pattern similar to those shown in Section 3.9 that will sum up to this number.
Show solution
Number Chosen: 250 25 25 50 50 50 25 25 Or 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10 10

Source solution page 32

8. Recall the sequence of Powers of 2 from Chapter 1, Table 1. Why is the Collatz conjecture correct for all the starting numbers in this sequence?
Show solution
when we divide 28 = 2x2x2x2x2x2x2x2 by 2 it become 27 and every time you divide by 2 the same will continue happening, until you are left with 2 which when divided by 2 will leave 1.

Source solution page 32

9. Check if the Collatz Conjecture holds for the starting number 100.
Show solution
100, 50, 25, 76, 38, 19, 58, 29, 88, 44, 22, 11, 34, 17, 52, 26, 13, 40, 20, 10, 5, 16, 8, 4, 2, 1.

Source solution page 32

10 Starting with 0, players alternate adding numbers between 1 and 3. The first person to reach 22 wins. What is the winning strategy now?
Show solution
Winning strategy is to be the first player. [13]

