New NCERT · Ganita Prakash · Chapter 3

A Peek Beyond the Point Class 7 Solutions

Complete question-by-question help, with full textbook crops that retain the diagrams, tables and surrounding information needed to solve each item.

74 solved items28 textbook pagesReviewed for 2026-27
Questions from Class 7 Maths Chapter 3, A Peek Beyond the Point
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Complete worked answers

Textbook page 2

Textbook page 2 · solved item 1

NCERT Class 7 Maths Chapter 3, solved question 1
Question from the current NCERT textbook

Which scale helped you measure the length of the screws accurately? Why?

Show solution

The scale with millimeter markings helped measure the length of the screws accurately because it allows for more precise and detailed measurements compared to scales with only centimeter markings.

Textbook page 2 · solved item 2

NCERT Class 7 Maths Chapter 3, solved question 2
Question from the current NCERT textbook

What is the meaning of 2 7 10 cm (the length of the first screw)?

Show solution

It means that the length of the screw is two and seven-tenth centimeters.

Textbook page 2 · solved item 3

NCERT Class 7 Maths Chapter 3, solved question 3
Question from the current NCERT textbook

Can you explain why the unit was divided into smaller parts to measure the screws?

Show solution

The unit was divided into smaller parts because the lengths of the screws were not whole centimetres. Smaller divisions, like millimetres, were needed to measure them more accurately.

Textbook page 2 · solved item 4

NCERT Class 7 Maths Chapter 3, solved question 4
Question from the current NCERT textbook

Measure the following objects using a scale and write their measurements in centimeters (as shown earlier for the lengths of the screws): pen, sharpener, and any other object of your choice.

Show solution

Pen: 14 cm Sharpener: 3.2 cm Eraser: 4.0 cm Notebook: 21cm

Textbook page 2 · solved item 5

NCERT Class 7 Maths Chapter 3, solved question 5
Question from the current NCERT textbook

Write the measurements of the objects shown in the picture:

Show solution

Eraser: 2.4 cm Pencil: 4.5 cm Chalk: 1.4 cm

Complete worked answers

Textbook page 4

Textbook page 4 · solved item 6

NCERT Class 7 Maths Chapter 3, solved question 6
Question from the current NCERT textbook

Arrange these lengths in increasing order: (a) 9 10 (b) 1 7 10 (c) 130 10 (d) 13 1 10 (e) 10 5 10 (f) 7 6 10 (g) 6 7 10 (h) 4 10

Show solution

(a) 9 10 = 0.9 (b) 1 7 10 = 17 10 = 1.7 (c) 130 10 = 13.0 (d) 13 1 10 = 131 10 = 13.1 (e) 10 5 10 = 105 10 = 10.5 (f) 7 6 10 = 76 10 = 7.6 (g) 6 7 10 = 67 10 = 6.7 (h) 4 10 = 0.4 0.4 < 0.9 < 1.7 < 6.7 < 7.6 < 10.5 < 13.0 < 13.1 or 4 10 < 9 10 < 1 7 10 < 6 7 10 < 7 6 10 < 10 5 10 < 130 10 < 13 1 10

Complete worked answers

Textbook page 5

Textbook page 5 · solved item 7

NCERT Class 7 Maths Chapter 3, solved question 7
Question from the current NCERT textbook

Arrange the following lengths in increasing order: 4 1 10, 4 10, 41 10, 41 1 10.

Show solution

4 1 10 = 41 10 = 4.1 4 10 = 0.4 41 10 = 4.1 41 1 10 = 411 10 = 41.1 0.4 < 4.1 = 4.1 < 41.1 or 4 10 < 4 1 10 = 41 10 < 41 1 10

Textbook page 5 · solved item 8

NCERT Class 7 Maths Chapter 3, solved question 8
Question from the current NCERT textbook

Sonu is measuring some of his body parts. The length of Sonu’s lower arm is 2 7 10 units, and that of his upper arm is 3 6 10 units. What is the total length of his arm?

Show solution

Lower arm = 2 7 10 units Upper arm = 3 6 10 units Total length of arms = 2 7 10 + 3 6 10 = (2 + 3) + ( 7 10 + 6 10) = 5 + 13 10 = 5 + 10 10 + 3 10 = 5 + 1 + 3 10 = 6 3 10 units.

Complete worked answers

Textbook page 6

Textbook page 6 · solved item 9

NCERT Class 7 Maths Chapter 3, solved question 9
Question from the current NCERT textbook

The lengths of the body parts of a honeybee are given. Find its total length. Head: 2 3 10 units Thorax: 5 4 10 units Abdomen: 7 5 10 units

Show solution

Total length of bee = Head + Thorax + Abdomen = 2 3 10 + 5 4 10 + 7 5 10 = (2 + 5 + 7) + ( 3 10 + 4 10 + 5 10) = 14 + ( 3+4+5 10 ) = 14 + 12 10 = 14 + 10 10 + 2 10 = 14 + 1 + 2 10 = 15 2 10 units.

Textbook page 6 · solved item 10

NCERT Class 7 Maths Chapter 3, solved question 10
Question from the current NCERT textbook

The length of Shylaja’s hand is 12 4 10 units, and her palm is 6 7 10units, as shown in the picture. What is the length of the longest (middle) finger?

Show solution

Length of hand = 12 4 10 units Length of palm = 6 7 10units Length of longest finger = Hand – Palm = 12 4 10 - 6 7 10 = (12 – 6) + ( 4 10 − 7 10) = 6 + −3 10 = 6 - 3 10 = 5 + 1 - 3 10 = 5 + 10 10 - 3 10 = 5 + 10− 3 10 = 5 + 7 10 = 5 7 10 units.

Complete worked answers

Textbook page 7

Textbook page 7 · solved item 11

NCERT Class 7 Maths Chapter 3, solved question 11
Question from the current NCERT textbook

Try computing the difference by converting both lengths to tenths. Length of hand = 12 4 10 units Length of palm = 6 7 10units

Show solution

Length of hand = 12 4 10 units = 124 10 units Length of palm = 6 7 10units = 67 10 units Length of longer finger = Hand – Palm = 124 10 - 67 10 = 124− 67 10 = 57 10 = 50 10 + 7 10 = 5 + 7 10 = 5 7 10 units.

Textbook page 7 · solved item 12

NCERT Class 7 Maths Chapter 3, solved question 12
Question from the current NCERT textbook

A Celestial Pearl Danio’s length is 2 4 10 cm, and the length of a Philippine Goby is 9 10 cm. What is the difference in their lengths?

Show solution

Celestial Pearl Dino’s length = 2 4 10 cm = 24 10 cm Philippine Goby’s length = 9 10 cm Difference in length = 24 10 - 9 10 = 24− 9 10 = 15 10 = 10 10 + 5 10 = 1 + 5 10 = 1 5 10 cm.

Textbook page 7 · solved item 13

NCERT Class 7 Maths Chapter 3, solved question 13
Question from the current NCERT textbook

How big are these fish compared to your finger?

Show solution

Celestial Pearl Dino = 24 10 cm = 2.4 cm Philippine Goby = 9 10 = 0.9 cm Little finger’s length = 2.7 cm Celestial Pearl Dino is 0.3 cm (2.7 – 2.4 = 0.3 cm) smaller than my little finger. Philippine Goby is 1.8 cm (2.7 – 0.9 = 1.8 cm) smaller than my little finger.

Textbook page 7 · solved item 14

NCERT Class 7 Maths Chapter 3, solved question 14
Question from the current NCERT textbook

Observe the given sequences of numbers. Identify the change after each term and extend the pattern: (a) 4, 4 3 10 , 4 6 10 , ………. (b) 8 2 10, 8 7 10, 9 2 10, ……….. (c) 7 6 10, 8 7 10, ……….. (d) 5 7 10, 5 4 10, ……….. (e) 13 5 10 ,13, 12 5 10 , ………. (f) 11 5 10 , 10 4 10 , 9 3 10 , ………..

Show solution

(a) 4, 4 3 10 , 4 6 10, ……….. Change = Addition of 3 10. 4, 4 3 10 , 4 6 10, 4 9 10, 5 2 10, 5 5 10, …… (b) 8 2 10, 8 7 10, 9 2 10, ……….. Change = Addition of 5 10. 8 2 10, 8 7 10, 9 2 10, 9 7 10 , 10 2 10, 10 7 10, …… (c) 7 6 10, 8 7 10, ……….. Change = Addition of 1 1 10. 7 6 10, 8 7 10, 9 8 10, 10 9 10, 12, 13 1 10, …….

(d) 5 7 10, 5 3 10, …… Change = Subtraction of 4 10. 5 7 10, 5 3 10, 4 9 10, 4 5 10, 4 1 10, 3 7 10, ……… (e) 13 5 10 ,13, 12 5 10 , ………. Change = Subtraction of 5 10. 13 5 10 ,13, 12 5 10 , 12, 11 5 10, 11, 10 5 10, 10, ……… (f) 11 5 10 , 10 4 10 , 9 , ……….. Change = Subtraction of 1 1 10. 11 5 10 , 10 4 10 , 9 3 10, 8 2 10, 7 1 10, 6, ……..

Complete worked answers

Textbook page 8

Textbook page 8 · solved item 15

NCERT Class 7 Maths Chapter 3, solved question 15
Question from the current NCERT textbook

What is the length of this smaller part? How many such smaller parts make a unit length?

Show solution

Length of each smaller part on splitting each one-tenth into 10 parts = 1 100. 100 such smaller parts make a unit length.

Textbook page 8 · solved item 16

NCERT Class 7 Maths Chapter 3, solved question 16
Question from the current NCERT textbook

How many one-hundredths make one-tenth? Can we also say that the length is 4 units and 45 one-hundredths? (Length is 4 units and 4 one-tenths and 5 one-hundredths)

Show solution

Number of one-hundredths in one-tenth = 1 100 ÷ 1 10 = 10. 4 units and 4 one-tenths and 5 one-hundredths = 4 + 4 10 + 5 100 = 4 + 0.4 + 0.45 = 4.45 units. 4 units and 45 one-hundredths = 4 + 45 100 = 4 + 0.45 = 4.45 units. Hence, 4 units and 4 one-tenths and 5 one-hundredths can also be written as 4 units and 45 one-hundredths.

Complete worked answers

Textbook page 9

Textbook page 9 · solved item 17

NCERT Class 7 Maths Chapter 3, solved question 17
Question from the current NCERT textbook

Observe the figure below. Notice the markings and the corresponding lengths written in the boxes when measured from 0. Fill the lengths in the empty boxes.

Show solution

From left to right, the empty boxes are 55/100, 155/100, 164/100, 202/100, and 240/100.

Textbook page 9 · solved item 18

NCERT Class 7 Maths Chapter 3, solved question 18
Question from the current NCERT textbook

For the lengths shown below write the measurements and read out the measures in words.

Show solution

5 3 10 7 100 = Five and three-tenths and seven-hundredths. 15 3 100 = Fifteen and three-hundredths.

Textbook page 9 · solved item 19

NCERT Class 7 Maths Chapter 3, solved question 19
Question from the current NCERT textbook

For the lengths shown below write the measurements and read out the measures in words. 55 100 155 100 164 100 202 100 240 100

Show solution

7 5 10 2 100 = Seven and five-tenths and two-hundredths. 9 80 100 = Nine and eighty-hundredths.

Complete worked answers

Textbook page 10

Textbook page 10 · solved item 20

NCERT Class 7 Maths Chapter 3, solved question 20
Question from the current NCERT textbook

In each group, identify the longest and the shortest lengths. Mark each length on the scale. (a) 3 10 , 3 100, 33 100 (b) 3 1 10, 30 10 , 1 3 10 (c) 45 100, 54 100, 5 10, 4 10 (d) 3 6 10, 3 6 100, 3 6 10 6 100 (e) 8 10 2 100, 9 100, 1 8 100 (f) 7 3 10 5 100, 7 5 10, 7 41 100 (g) 65 10 15 100, 5 87 100, 5 7 100

Show solution

(a) 3 10 , 3 100, 33 100 3 10 = 30 100 ; 3 100 ; 33 100 Longest length = 33 100 Shortest length = 3 100 (b) 3 1 10, 30 10 , 1 3 10 3 1 10 = 31 10 = 3.1 ; 30 10 = 3 ; 1 3 10 = 13 10 = 1.3 Longest length = 3 1 10 3 10 3 100 33 100 Shortest length = 1 3 10 (c) 45 100, 54 100, 5 10, 4 10 45 100 ; 54 100 ; 5 10 = 50 100 ; 4 10 = 40 100 Longest length = 54 100 Shortest length = 40 100 (d) 3 6 10, 3 6 100, 3 6 10 6 100 3 6 10 = 36 10 ; 3 6 100 = 30 10 6 100 ; 3 6 10 6 100 = 36 10 6 100 Largest number = 3 6 10 6 100 Smallest number = 3 6 100 30 10 1 3 10 3 1 10 4 10 45 10 5 10 54 10 3 6 100 3 6 10 3 6 10 6 100 (e) 8 10 2 100, 9 100, 1 8 100 Largest number = 1 8 100 Smallest number = 9 100 (f) 7 3 10 5 100, 7 5 10, 7 41 100 7 3 10 5 100 = 73 10 5 100 ; 7 5 10 = 75 10 7 41 100 = 7 + 41 100 = 70 10 + 41 100 = 70 10 + 40 100 + 1 100 = 70 10 + 4 10 + 1 100 = 74 10 + 1 100 = 74 10 1 100 Largest number = 7 5 10 Smallest number = 7 3 10 5 100 (g) 65 10 15 100, 5 87 100, 5 7 100 65 10 15 100 = 65 10 + 15 100 = 65 10 + 10 100 + 5 100 = 65 10 + 1 10 + 5 100 = 66 10 + 5 100 = 66 10 5 100 5 87 100 = 5 + 87 100 = 5 + 80 100 + 7 100 = 5 + 8 10 + 7 100 = 5 8 10 7 100 5 7 100 Largest number = 65 10 15 100 Smallest number = 5 7 100 9 100 8 10 2 100 1 8 100 7 3 10 5 100 7 41 100 7 5 10

Complete worked answers

Textbook page 11

Textbook page 11 · solved item 21

NCERT Class 7 Maths Chapter 3, solved question 21
Question from the current NCERT textbook

What will be the sum of 15 3 10 4 100 and 2 6 10 8 100?

Show solution

Method 1: 15 3 10 4 100 + 2 6 10 8 100 = (15 + 2) + ( 3 10 + 6 10 ) + ( 4 100 + 8 100 ) = 17 + 9 10 + 12 100 = 17 + 9 10 + 10 100 + 2 100 = 17 + 9 10 + 1 10 + 2 100 = 17 + 10 10 + 2 100 = 17 + 1 + 2 100 = 18 + 2 100. Method 2: 15 3 10 4 100 + 2 6 10 8 100 = 15 3 10 4 100 + 2 6 10 8 100 = 17 9 10 12 100 = 17 10 10 2 100 = 18 2 100.

Complete worked answers

Textbook page 12

Textbook page 12 · solved item 22

NCERT Class 7 Maths Chapter 3, solved question 22
Question from the current NCERT textbook

Are both these methods different?

Show solution

No, both methods are the same in logic and result but differ in structure. Method 1 uses a step-by-step horizontal layout for addition, while Method 2 uses a vertical layout.

Complete worked answers

Textbook page 13

Textbook page 13 · solved item 23

NCERT Class 7 Maths Chapter 3, solved question 23
Question from the current NCERT textbook

Solve this by converting to hundredths. 25 9 10 - 6 4 10 7 100

Show solution

25 9 10 = 25 90 100 ; 6 4 10 7 100 = 6 47 100 25 9 10 - 6 4 10 7 100 = 25 90 100 - 6 47 100 = (25 – 6) + ( 90 100 − 47 100 ) = 19 + 43 100 = 19 43 100 . 65 10 15 100 7 41 100 Figure it out

Textbook page 13 · solved item 24

NCERT Class 7 Maths Chapter 3, solved question 24
Question from the current NCERT textbook

Find the sums and differences: (a) 3 10 + 3 4 100 (b) 9 5 10 7 100 + 2 1 10 3 100 (c) 15 6 10 4 100 + 14 3 10 6 100 (d) 7 7 100 – 4 4 100 (e) 8 6 100 – 5 3 100 (f) 12 6 100 2 100 - 9 10 9 100

Show solution

(a) 3 10 + 3 4 100 = 30 100 + 3 + 4 100 = 3 + ( 30 100 + 4 100 ) = 3 + 34 100 = 3 34 100. (b) 9 5 10 7 100 + 2 1 10 3 100 = (9 + 2) + ( 5 10 + 1 10 ) + ( 7 100 + 3 100 ) = 11 + ( 5+1 10 ) + ( 7+3 100 ) = 11 + 6 10 + 10 100 = 11 + 6 10 + 1 10 = 11 + 7 10 = 11 7 10. (c) 15 6 10 4 100 + 14 3 10 6 100 = (15 + 14) + ( 6 10 + 3 10 ) + ( 4 100 + 6 100 ) = 29 + ( 6+3 10 ) + ( 4+6 100) = 29 + 9 10 + 10 100 = 29 + 9 10 + 1 10 = 29 + 10 10 = 29 + 1 = 30.

(d) 7 7 100 – 4 4 100 = (7 – 4) + ( 7 100 − 4 100 ) = 3 + 3 100 = 3 3 100 . (e) 8 6 100 – 5 3 100 = (8 – 5) + ( 6 100 − 3 100 ) = 3 + 3 100 = 3 3 100 . (f) 12 6 10 2 100 - 9 10 9 100 = 12 62 100 – 99 100 = 11 + 1 + 62 100 – ( 99 100 ) = 11 + 100 100 + 62 100 – ( 99 100 ) = 11 + 162 100 - ( 99 100 ) = 11 + ( 162 100 − 99 100 ) = 11 + 63 100 = 11 63 100.

Complete worked answers

Textbook page 15

Textbook page 15 · solved item 25

NCERT Class 7 Maths Chapter 3, solved question 25
Question from the current NCERT textbook

Can we extend this further?

Show solution

Yes, it can be extended on both sides infinitely.

Complete worked answers

Textbook page 16

Textbook page 16 · solved item 26

NCERT Class 7 Maths Chapter 3, solved question 26
Question from the current NCERT textbook

We can ask similar questions about fractional parts: (a) How many thousandths make one unit? (b) How many thousandths make one tenth? (c) How many thousandths make one hundredth? (d) How many tenths make one ten? (e) How many hundredths make one ten?

Show solution

(a) Since, 1 1000 × 1000 = 1. Therefore, 1000 thousandths make one unit. (b) Since, 1 1000 × 100 = 1 10. Therefore, 100 thousandths make one tenth. (c) Since, 1 1000 × 10 = 1 100. Therefore, 10 thousandths make one hundredth. 1 1000 1 10,000 1,00,000 10,00,000 (d) Since, 1 10 × 100 = 10. Therefore, 100 tenths make one ten.

(e) Since, 1 100 × 1000 = 10. Therefore, 1000 tenths make one ten.

Textbook page 16 · solved item 27

NCERT Class 7 Maths Chapter 3, solved question 27
Question from the current NCERT textbook

We can ask similar questions about fractional parts: (a) How many hundredths make one unit? (b) How many tenths make one unit? (c) How many tenths make one hundredth? (d) How many hundredths make one tenth?

Show solution

(a) Since, 1 100 × 100 = 1. Therefore, 100 hundredths make one unit. (b) Since, 1 10 × 10 = 1. Therefore, 10 tenths make one unit. (c) Since, 1 10 × 1 10 = 1 100. Therefore, 1 10 tenths make one hundredth. (d) Since, 1 100 × 10 = 1 10. Therefore, 10 hundredths make one tenth.

Complete worked answers

Textbook page 18

Textbook page 18 · solved item 28

NCERT Class 7 Maths Chapter 3, solved question 28
Question from the current NCERT textbook

Make a place value table similar to the one above. Write each quantity in decimal form and in terms of place value and read the number: (a) 2 ones, 3 tenths and 5 hundredths (b) 1 ten and 5 tenths (c) 4 ones and 6 hundredths (d) 1 hundred, 1 one and 1 hundredth (e) 8 100 and 9 10 (f) 5 100 (g) 1 10 (h) 2 1 100, 4 1 10 and 7 1 1000

Show solution

Quantity Decimal Notation (a) 2 ones, 3 tenths and 5 hundredths (2 + 3 10 + 5 100) 2.35 b) 1 ten and 5 tenths (10 + 0 + 5 10) 10.5 (c) 4 ones and 6 hundredths (4 + 0 + 6 100) 4.06 (d) 1 hundred, 1 one and 1 hundredth (100 + 0 + 1 + 0 + 1 100) 101.01 (e) 8 100 and 9 10 ( 9 10 + 8 100) 0.98 (f) 5 100 0.05 (g) 1 10 0.1 (h) 2 1 100, 4 1 10 and 7 1 1000 ( 4 10 + 2 100 + 7 1000) 0.427 (a) 2.35 – Two point three five.

(b) 10.35 – Ten point three five. (c) 4.06 – Four point zero six. (d) 101.01 – One hundred one point zero one. (e) 0.98 – zero point nine eight. (f) 0.05 – zero-point zero five. (g) 0.1 – zero point one. (h) 0.427 – zero point four two seven. Decimal Number Hundreds Tens Units Tenths Hundredths Thousandths (a) 2.35 2 × 1 3 × 1 10 5 × 1 100 (b) 10.5 1 × 10 0 × 1 5 × 1 10 (c) 4.06 4 × 1 0 × 1 10 6 × 1 100 (d) 101.01 1 × 100 0 × 10 1 × 1 0 × 1 10 1 × 1 100 (e) 0.98 9 × 1 10 8 × 1 100 (f) 0.05 0 × 1 10 5 × 1 100 (g) 0.1 1 × 1 10 (h) 0.427 4 × 1 10 2 × 1 100 7 × 1 1000

Complete worked answers

Textbook page 19

Textbook page 19 · solved item 29

NCERT Class 7 Maths Chapter 3, solved question 29
Question from the current NCERT textbook

Write these quantities in decimal form: (a) 234 hundredths, (b) 105 tenths.

Show solution

(a) 234 hundredths = 234 100 = 2.34 (b) 105 tenths = 105 10 = 10.5

Complete worked answers

Textbook page 20

Textbook page 20 · solved item 30

NCERT Class 7 Maths Chapter 3, solved question 30
Question from the current NCERT textbook

Fill in the blanks below (mm <–> cm) 12 mm = 1.2 cm 56 mm = 5.6 cm 70 mm = _______ ________ = 0.9 cm 134 mm =__________ ________ = 203.6 cm

Show solution

70 mm = 70 10 cm = 7cm 0.9 cm = (0.9 × 10) mm = ( 9 10 × 10) mm = 9 mm 134 mm = 134 10 cm = 13.4 cm 203.6 cm = (203.6 × 10) mm = ( 2036 10 × 10) mm = 2036 mm 12 mm = 1.2 cm 56 mm = 5.6 cm 70 mm = 7cm 9 mm = 0.9 cm 134 mm = 13.4 cm 2036 mm = 203.6 cm

Complete worked answers

Textbook page 21

Textbook page 21 · solved item 31

NCERT Class 7 Maths Chapter 3, solved question 31
Question from the current NCERT textbook

Fill in the blanks below (cm <–> m): 36 cm = _______ 50 cm = _______ _______ = 0.89 m 4 cm = _______ 325 cm = _______ ________ = 2.07 m

Show solution

36 cm = 36 100 m = ( 30 100 + 6 100) m = ( 3 10 + 6 100) m = 0.36 m 50 cm = 50 100 m = 5 10 m = 0.5 m 0.89 m = (0.89 × 100) cm = ( 89 100 × 100) cm = 89 cm 4 cm = 4 100 m = 0.04 m 325 cm = 325 100 m = ( 300 100 + 20 100 + 5 100) m = (3 + 2 10 + 5 100) m = 3.25 m 2.07 m = (2.07 × 100) cm = ( 207 100 × 100) cm = 207 cm 36 cm = 0.36 m 50 cm = 0.5 m 89 cm = 0.89 m 4 cm = 0.04 m 325 cm = 3.25 m 207 cm = 2.07 m

Textbook page 21 · solved item 32

NCERT Class 7 Maths Chapter 3, solved question 32
Question from the current NCERT textbook

How many mm does 1 meter have?

Show solution

1 m = (1 × 100) cm = 100 cm = (100 × 10) mm = 1000 mm.

Textbook page 21 · solved item 33

NCERT Class 7 Maths Chapter 3, solved question 33
Question from the current NCERT textbook

Can we write 1 mm = 1 1000 m?

Show solution

Yes, 1 mm can be written as 1 1000 m. Because 1 mm = 1 10 cm = 1 10 × 100 m = 1 1000 m

Complete worked answers

Textbook page 22

Textbook page 22 · solved item 34

NCERT Class 7 Maths Chapter 3, solved question 34
Question from the current NCERT textbook

Fill in the blanks below (g <–> kg) 465 g = _______ 68 g = _________ 1560 g = ________ 704 g = _______ ________ = 0.56 kg _______ = 2.5 kg

Show solution

465 g = 465 1000 kg = ( 400 1000 + 60 1000 + 5 1000) kg = ( 4 10 + 6 100 + 5 1000) kg = 0.465 kg 68 g = 68 1000 kg = ( 60 1000 + 8 1000) kg = ( 6 100 + 8 1000) kg = 0.068 kg 1560 g = 1560 1000 kg = ( 1000 1000 + 500 1000 + 60 1000) kg = (1 + 5 10 + 6 100) kg = 1.56 kg 704 g = 704 1000 kg = ( 700 1000 + 4 1000) kg = ( 7 10 + 4 1000) kg = 0.704 kg 0.56 kg = (0.56 × 1000) g = ( 56 100 × 1000) g = 560 g 2.5 kg = (2.5 × 1000) g = ( 25 10 × 1000) g = 2500 g 465 g = 0.465 kg 68 g = 0.068 kg 1560 g = 1.56 kg 704 g = 0.704 kg 560 g = 0.56 kg 2500 g = 2.5 kg

Complete worked answers

Textbook page 24

Textbook page 24 · solved item 35

NCERT Class 7 Maths Chapter 3, solved question 35
Question from the current NCERT textbook

Fill in the blanks below (rupee <–> paise) 10 p = __________ _______p = ₹ 0.05 ________p = ₹ 0.36 _________ = ₹ 0.50 99 p = _________ 250 p = _________

Show solution

10 p = ₹ 10 100 = ₹ 1 10 = ₹ 0.1 ₹ 0.05 = (0.05 × 100) p = ( 5 100 × 100) p = 5 p ₹ 0.36 = (0.36 × 100) p = ( 36 100 × 100) p = 36 p ₹ 0.50 = (0.50 × 100) p = ( 50 100 × 100) p = 50 p 99 p = ₹ 99 100 = ₹ ( 90 100 + 9 100) = ₹ ( 9 10 + 9 100) = ₹ 0.99 250 p = ₹ 250 100 = ₹ ( 200 100 + 50 100) = ₹ (2 + 5 10) = ₹ 2.5 10 p = ₹ 0.1 5 p = ₹ 0.05 36 p = ₹ 0.36 50 p = ₹ 0.50 99 p = ₹ 0.99 250 p = ₹ 2.5

Complete worked answers

Textbook page 25

Textbook page 25 · solved item 36

NCERT Class 7 Maths Chapter 3, solved question 36
Question from the current NCERT textbook

Name all the divisions between 1 and 1.1 on the number line.

Show solution

1 – 1.01 – 1.02 – 1.03 – 1.04 – 1.05 – 1.06 – 1.07 – 1.08 – 1.09 -1.1

Textbook page 25 · solved item 37

NCERT Class 7 Maths Chapter 3, solved question 37
Question from the current NCERT textbook

Identify and write the decimal numbers against the letters.

Show solution

The marked decimals are A = 5.09, B = 5.13, C = 5.20, and D = 5.31.

Complete worked answers

Textbook page 26

Textbook page 26 · solved item 38

NCERT Class 7 Maths Chapter 3, solved question 38
Question from the current NCERT textbook

Can you tell which of these is the smallest and which is the largest? 0.2, 0.20, 0.200, 0.02, 0.002

Show solution

0.002 < 0.02 < 0.2 = 0.20 = 0.200 Smallest = 0.002 Largest = 0.2 5.09 5.13 5.2 5.31

Textbook page 26 · solved item 39

NCERT Class 7 Maths Chapter 3, solved question 39
Question from the current NCERT textbook

Which of these are the same: 4.5, 4.05, 0.405, 4.050, 4.50, 4.005, 04.50?

Show solution

Decimal Number Units Tenths Hundredths Thousandths 4.5 4 5 4.05 4 0 5 0.405 0 4 0 5 4.050 4 0 5 0 4.50 4 5 0 4.005 4 0 0 5 04.50 4 5 0 Therefore, 4.50 = 04.50 & 4.05 = 4.050

Textbook page 26 · solved item 40

NCERT Class 7 Maths Chapter 3, solved question 40
Question from the current NCERT textbook

Identify the decimal number in the last number line in Figure (b) denoted by ‘?’.

Show solution

The successive number lines narrow the interval from 3 to 4, then 3.0 to 3.1, and then 3.05 to 3.06. The marked value is 3.059.

Textbook page 26 · solved item 41

NCERT Class 7 Maths Chapter 3, solved question 41
Question from the current NCERT textbook

Make such number lines for the decimal numbers: (a) 9.876 (b) 0.407.

Show solution

(a) 9.876 (b) 0.407 3 4 3.0 3.1 3.05 3.06 3.059 0 10 9 10 9.8 9.9 9.87 9.88 9.876 0 10 0 1 0.4 0.5 0.40 0.41 0.407

Textbook page 26 · solved item 42

NCERT Class 7 Maths Chapter 3, solved question 42
Question from the current NCERT textbook

In the number line shown below, what decimal numbers do the boxes labelled ‘a’, ‘b’, and ‘c’ denote?

Show solution

Divisions between 5 and 10 = 10 Each division= 10−5 10 = 5 10 = 0.5 units Therefore, a = 5 + (2 × 0.5) = 5 + 1 = 6 b = 5 + (5 × 0.5) = 5 + 2.5 = 7.5 c = 5 + (9 × 0.5) = 5 + 4.5 = 9.5

Complete worked answers

Textbook page 27

Textbook page 27 · solved item 43

NCERT Class 7 Maths Chapter 3, solved question 43
Question from the current NCERT textbook

Using similar reasoning find out the decimal numbers in the boxes below.

Show solution

(i) Divisions between 8 and 8.1 = 10 Each division = (8.1 – 8) ÷ 10 = 0.1 ÷ 10 = 1 10 × 1 10 = 1 100 = 0.01 Therefore, d = 8 + 0.01 = 8.01. e = 8 + (5 × 0.01) = 8 + 0.05 = 8.05. (ii) Divisions between 4.3 and 4.8 = 10 Each division = (4.8 – 4.3) ÷ 10 = 0.5 ÷ 10 = 5 10 × 1 10 = 5 100 = 0.05 Therefore, f = 4.3 + 0.05 = 4.35. g = 4.3 + (4 × 0.05) = 4.3 + 0.2 = 4.50. h = 4.3 + (11 × 0.05) = 4.3 + 0.55 = 4.85.

Q. Which is larger: 6.456 or 6.465? Solution Comparing both numbers: Units place – Both have 6 in the units place. Tenths place – Both have 4 in the tenths place. Hundredths place – 6.456 has 5 in the hundredths place, while 6.465 has 6. Since 6 > 5, 6.465 is greater than 6.456 at the hundredths place.

Therefore, 6.465 is the larger number.

Complete worked answers

Textbook page 28

Textbook page 28 · solved item 44

NCERT Class 7 Maths Chapter 3, solved question 44
Question from the current NCERT textbook

Why can we stop comparing at this point? Can we be sure that whatever digits are there after this will not affect our conclusion?

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When comparing decimal numbers, stop at the place value where the digits are different. The number with the larger digit at that place is the greater number.

Textbook page 28 · solved item 45

NCERT Class 7 Maths Chapter 3, solved question 45
Question from the current NCERT textbook

Which decimal number is greater? (a) 1.23 or 1.32 (b) 3.81 or 13.800 (c) 1.009 or 1.090

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(a) 1.23 or 1.32 Comparing both numbers: Units place – Both have 1 in the units place. Tenths place – 1.23 has 2 in the tenths place, while 1.32 has 3. Since 3 > 2, 1.32 is greater than 1.23 at the tenths place. Therefore, 1.32 is the larger number. (b) 3.81 or 13.800 = 03.81 or 13.800 Comparing both numbers: Tenths place – 3.81 has 0 in the tens place while 13.800 has 1.

Since 0 < 1, 13.800 is greater than 3.81 at the tens place. Therefore, 13.800 is the larger number. (c) 1.009 or 1.090 Comparing both numbers: Units place – Both have 1 in the units place. Tenths place – Both have 0 in the tenths place. Hundredths place – 1.009 has 0 in the hundredths place while 1.090 has 9.

Since 0 < 9, 1.090 is greater than 1.009 at the hundredths place. Therefore, 1.090 is the larger number.

Textbook page 28 · solved item 46

NCERT Class 7 Maths Chapter 3, solved question 46
Question from the current NCERT textbook

Which of the above is closest to 1.09? (Decimal numbers: 0.9, 1.1, 1.01, and 1.11)

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Arranging all numbers in ascending order: 0.9 < 1.01 < 1.09 < 1.1 < 1.11 Here, neighbours of 1.09 are 1.01 and 1.1. 1.1 (or 1.10) is 1 100 away from 1.09 1.01 is 8 100 away from 1.09 Therefore, 1.1 is closest to 1.09.

Textbook page 28 · solved item 47

NCERT Class 7 Maths Chapter 3, solved question 47
Question from the current NCERT textbook

Which among these is closest to 4: 3.56, 3.65, 3.099?

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Arranging all numbers in ascending order: 3.099 < 3.56 < 3.65 Now, compare the distance of each number from 4: 4 − 3.099 = 0.901 4 − 3.56 = 0.44 4 − 3.65 = 0.35 Among these, 3.65 is the smallest distance from 4. Therefore, 3.65 is closest to 4.

Textbook page 28 · solved item 48

NCERT Class 7 Maths Chapter 3, solved question 48
Question from the current NCERT textbook

Which among these is closest to 1: 0.8, 0.69, 1.08?

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Arranging all numbers in ascending order: 0.69 < 0.8 < 1.08 Now, compare the distance of each number from 1: 1 − 0.69 = 0.31 1 − 0.8 = 0.2 1.08 − 1 = 0.08 Among these, 1.08 is the smallest distance from 1. Therefore, 1.08 is closest to 1

Textbook page 28 · solved item 49

NCERT Class 7 Maths Chapter 3, solved question 49
Question from the current NCERT textbook

In each case below use the digits 4, 1, 8, 2, and 5 exactly once and try to make a decimal number as close as possible to 25.

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Using each digit once, the entries shown are 25.148, 8.542, and 124.58 for the three box arrangements.

Complete worked answers

Textbook page 30

Textbook page 30 · solved item 50

NCERT Class 7 Maths Chapter 3, solved question 50
Question from the current NCERT textbook

Write the detailed place value computation for 84.691 – 77.345, and its compact form.

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Figure it Out

Textbook page 30 · solved item 51

NCERT Class 7 Maths Chapter 3, solved question 51
Question from the current NCERT textbook

1. Find the sums: (a) 5.3 + 2.6 (b) 18 + 8.8 (c) 2.15 + 5.26 (d) 9.01 + 9.10 (e) 29.19 + 9.91 (f) 0.934 + 0.6 (g) 0.75 + 0.03 (h) 6.236 + 0.487

Show solution

(a) 5.3 + 2.6 = 7.9 2 5 1 4 8 8 5 4 2 1 2 4 5 8 5.3 + 2.6 7.9 84.691 - 77.345 7.346 7 1 8 1 (b) 18 + 8.8 = 18.0 + 8.8 = 26.8 (c) 2.15 + 5.26 = 7.41 (d) 9.01 + 9.10 = 18.11 (e) 29.19 + 9.91 = 39.10 (f) 0.934 + 0.6 = 1.534 (g) 0.75 + 0.03 = 0.78 18.0 + 8.8 26.8 1 2.15 + 5.26 7.41 1 09.01 + 9.10 18.11 1 29.19 + 9.91 39.10 1 1 1 0.934 + 0.6 1.534 1 0.75 + 0.03 0.78 (h) 6.236 + 0.

487 = 6.723

Textbook page 30 · solved item 52

NCERT Class 7 Maths Chapter 3, solved question 52
Question from the current NCERT textbook

Find the differences: (a) 5.6 – 2.3 (b) 18 – 8.8 (c) 10.4 – 4.5 (d) 17 – 16.198 (e) 17 – 0.05 (f) 34.505 – 18.1 (g) 9.9 – 9.09 (h) 6.236 – 0.487

Show solution

(a) 5.6 – 2.3 = 3.3 (b) 18 – 8.8 = 9.2 (c) 10.4 – 4.5 = 5.9 (d) 17 – 16.198 = 0.802 6.236 + 0.487 6.723 1 1 5.6 - 2.3 3.3 17.000 - 16.198 0.802 6 9 9 10 18.0 - 8.8 9.2 7 10 10.4 - 4.5 5.9 0 9 14 (e) 17 – 0.05 = 16.95 (f) 34.505 – 18.1 = 16.405 (g) 9.9 – 9.09 = 0.81 (h) 6.236 – 0.487 = 5.749

Textbook page 30 · solved item 53

NCERT Class 7 Maths Chapter 3, solved question 53
Question from the current NCERT textbook

Continue this sequence and write the next 3 terms. (Sequence - 4.4, 4.8. 5.2, 5.6, 6.0, ...)

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Sequence: 4.4, 4.8, 5.2, 5.6, 6.0, ... Each term increases by 0.4. Next after 6.0: 6.0 + 0.4 = 6.4 Next: 6.4 + 0.4 = 6.8 Next: 6.8 + 0.4 = 7.2 Therefore, Next 3 terms are 6.4, 6.8, 7.2. 17.00 - 0.05 6 9 10 16.95 9.90 - 9.09 8 10 0.81 6.236 - 0.487 5 11 12 16 5.749 34.505 - 18.100 16.405 2 14

Complete worked answers

Textbook page 31

Textbook page 31 · solved item 54

NCERT Class 7 Maths Chapter 3, solved question 54
Question from the current NCERT textbook

Similarly, identify the change and write the next 3 terms for each sequence given below. Try to do this computation mentally. (a) 4.4, 4.45, 4.5, ... (b) 25.75, 26.25, 26.75, ... (c) 10.56, 10.67, 10.78, ... (d) 13.5, 16, 18.5, ... (e) 8.5, 9.4, 10.3, ... (f) 5, 4.95, 4.90, ... (g) 12.45, 11.95, 11.45, ... (h) 36.5, 33, 29.5, ….

Show solution

(a) 4.4, 4.45, 4.5, ... Each term increases by 0.05 Next after 4.5: 4.5 + 0.05 = 4.55 Next: 4.55 + 0.05 = 4.6 Next: 4.6 + 0.05 = 4.65 Therefore, Next 3 terms are 4.55, 4.6, 4.65 (b) 25.75, 26.25, 26.75, ... Each term increases by 0.5 Next after 26.75: 26.75 + 0.5 = 27.25 Next: 27.25 + 0.5 = 27.75 Next: 27.75 + 0.5 = 28.25 Therefore, Next 3 terms are 27.25, 27.75, 28.25 (c) 10.56, 10.67, 10.78, ...

Each term increases by 0.11 Next after 10.78: 10.78 + 0.11 = 10.89 Next: 10.89 + 0.11 = 11.00 Next: 11.00 + 0.11 = 11.11 Therefore, Next 3 terms are 10.89, 11.00, 11.11 (d) 13.5, 16, 18.5, ... Each term increases by 2.5 Next after 18.5: 18.5 + 2.5 = 21.0 Next: 21.0 + 2.5 = 23.5 Next: 23.5 + 2.5 = 26.0 Therefore, Next 3 terms are 21.0, 23.5, 26.0 (e) 8.5, 9.4, 10.3, ...

Each term increases by 0.9 Next after 10.3: 10.3 + 0.9 = 11.2 Next: 11.2 + 0.9 = 12.1 Next: 12.1 + 0.9 = 13.0 Therefore, Next 3 terms are 11.2, 12.1, 13.0 (f) 5, 4.95, 4.90, ... Each term decreases by 0.05 Next after 4.90: 4.90 − 0.05 = 4.85 Next: 4.85 − 0.05 = 4.80 Next: 4.80 − 0.05 = 4.75 Therefore, Next 3 terms are 4.85, 4.80, 4.75 (g) 12.45, 11.95, 11.45, ...

Each term decreases by 0.5 Next after 11.45: 11.45 − 0.5 = 10.95 Next: 10.95 − 0.5 = 10.45 Next: 10.45 − 0.5 = 9.95 Therefore, Next 3 terms are 10.95, 10.45, 9.95 (h) 36.5, 33, 29.5, … Each term decreases by 3.5 Next after 29.5: 29.5 − 3.5 = 26.0 Next: 26.0 − 3.5 = 22.5 Next: 22.5 − 3.5 = 19.0 Therefore, Next 3 terms are 26.0, 22.5, 19.0

Textbook page 31 · solved item 55

NCERT Class 7 Maths Chapter 3, solved question 55
Question from the current NCERT textbook

Make your own sequences and challenge your classmates to extend the pattern.

Show solution

Some more sequences and their solutions: (i) 7.2, 7.5, 7.8, ... Each term increases by 0.3 Next after 7.8: 7.8 + 0.3 = 8.1 Next: 8.1 + 0.3 = 8.4 Next: 8.4 + 0.3 = 8.7 Therefore, Next 3 terms are 8.1, 8.4, 8.7 (ii) 15, 14.6, 14.2, ... Each term decreases by 0.4 Next after 14.2: 14.2 − 0.4 = 13.8 Next: 13.8 − 0.4 = 13.4 Next: 13.4 − 0.4 = 13.0 Therefore, Next 3 terms are 13.8, 13.4, 13.0 (iii) 22.1, 23.3, 24.5, ...

Each term increases by 1.2 Next after 24.5: 24.5 + 1.2 = 25.7 Next: 25.7 + 1.2 = 26.9 Next: 26.9 + 1.2 = 28.1 Therefore, Next 3 terms are 25.7, 26.9, 28.1 (iv) 0.5, 1.0, 1.5, ... Each term increases by 0.5 Next after 1.5: 1.5 + 0.5 = 2.0 Next: 2.0 + 0.5 = 2.5 Next: 2.5 + 0.5 = 3.0 Therefore, Next 3 terms are 2.0, 2.5, 3.0 (v) 18.25, 17.75, 17.25, ...

Each term decreases by 0.5 Next after 17.25: 17.25 − 0.5 = 16.75 Next: 16.75 − 0.5 = 16.25 Next: 16.25 − 0.5 = 15.75 Therefore, Next 3 terms are 16.75, 16.25, 15.75

Textbook page 31 · solved item 56

NCERT Class 7 Maths Chapter 3, solved question 56
Question from the current NCERT textbook

What do you think about this claim? Verify if this is true for these numbers. Will it work for any 2 decimal numbers? (Claim: If we add two decimal numbers, then the sum will always be greater than the sum of their whole number parts. Also, the sum will always be less than 2 more than the sum of their whole number parts.)

Show solution

Both the claims hold true. Verifying for 25.936 and 8.202: Number 1 Number 2 Sum Sum of whole parts Is sum ≥ whole parts? Is sum < whole parts +2 25.936 8.202 34.138 25 + 8 = 33 34.138 > 33 34.138 < 35 Verifying with other numbers:

Textbook page 31 · solved item 57

NCERT Class 7 Maths Chapter 3, solved question 57
Question from the current NCERT textbook

What about for the sum of 25.93603259 and 8.202?

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Number 1 Number 2 Sum Sum of whole parts Is sum ≥ whole parts? Is sum < whole parts +2 25.93603259 8.202 34.13803259 25 + 8 = 33 34.13803259 > 33 34.13803259 < 35 Number 1 Number 2 Sum Sum of whole parts Is sum ≥ whole parts? Is sum < whole parts +2 3.6 2.4 6.0 3 + 2 = 5 6 > 5 6 < 7 12.34 7.56 19.90 12 + 7 = 19 19.90 > 19 19.90 < 21 7.99 8.99 16.98 7 + 8 = 15 16.98 > 15 16.98 < 17

Complete worked answers

Textbook page 33

Textbook page 33 · solved item 58

NCERT Class 7 Maths Chapter 3, solved question 58
Question from the current NCERT textbook

Where else can we see such ‘non-decimals’ with a decimal-like notation?

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(i) Train or flight schedules like 08.20 or 17.55 are in HH.MM format, not decimal. (ii) Software versions like 3.6.2 version number—not a decimal, but a versioning system (3 major, 6 minor, 2 patch updates). (iii) In books and chapter like Chapter 5.4 = Chapter 5, Section 4. Figure it out

Textbook page 33 · solved item 59

NCERT Class 7 Maths Chapter 3, solved question 59
Question from the current NCERT textbook

1. Convert the following fractions into decimals: (a) 5 10 (b) 16 1000 (c) 12 10 (d) 254 1000

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(a) 5 10 = 0.5 (b) 16 1000 = 0.016 (c) 12 10 = 1.2 (d) 254 1000 = 0.254

Complete worked answers

Textbook page 34

Textbook page 34 · solved item 60

NCERT Class 7 Maths Chapter 3, solved question 60
Question from the current NCERT textbook

2. Convert the following decimals into a sum of tenths, hundredths and thousandths: (a) 0.34 (b) 1.02 (c) 0.8 (d) 0.362

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(a) 0.34 = (3 × 1 10) + (4 × 1 100). (b) 1.02 = (1 × 1) + (2 × 1 100). (c) 0.8 = (8 × 1 10). (d) 0.362 = (3 × 1 10) + (6 × 1 100) + (2 × 1 1000).

Textbook page 34 · solved item 61

NCERT Class 7 Maths Chapter 3, solved question 61
Question from the current NCERT textbook

3. What decimal number does each letter represent in the number line below?

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Divisions between 6.4 and 6.6 = 8 Each division = 6.6−6.4 8 = 0.2 8 = 2 80 = 0.025 Therefore, a = 6.4 + (2 × 0.025) = 6.4 + 0.050 = 6.425. c = 6.4 + (5 × 0.025) = 6.4 + 0.125 = 6.525. b = 6.4 + (6 × 0.025) = 6.4 + 0.150 = 6.550.

Textbook page 34 · solved item 62

NCERT Class 7 Maths Chapter 3, solved question 62
Question from the current NCERT textbook

4. Arrange the following quantities in descending order: (a) 11.01, 1.011, 1.101, 11.10, 1.01 (b) 2.567, 2.675, 2.768, 2.499, 2.698 (c) 4.678 g, 4.595 g, 4.600 g, 4.656 g, 4.666 g (d) 33.13 m, 33.31 m, 33.133 m, 33.331 m, 33.313 m

Show solution

(a) 11.10 > 11.01 > 1.101 > 11.011 > 1.01. (b) 2.768 > 2.698 > 2.675 > 2.567 > 2.499. (c) 4.678 g > 4.666 g > 4.656 g > 4.600 g > 4.595 g. (d) 33.331 m > 33.313 m > 33.31 m > 33.133 m > 33.13 m.

Textbook page 34 · solved item 63

NCERT Class 7 Maths Chapter 3, solved question 63
Question from the current NCERT textbook

5. Using the digits 1, 4, 0, 8, and 6 make: (a) the decimal number closest to 30 (b) the smallest possible decimal number between 100 and 1000.

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(a) Possible numbers: 14.860, 40.168 30 – 14.860 = 15.14 40.168 – 30 = 10.168 Hence, 40.168 is the closet number to 30. (b) Smallest number between 100 and 1000 = 104.68

Textbook page 34 · solved item 64

NCERT Class 7 Maths Chapter 3, solved question 64
Question from the current NCERT textbook

6. Will a decimal number with more digits be greater than a decimal number with fewer digits?

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Not always. A number with more decimal digits may be smaller. Example: 0.9 has 1 decimal digit. 0.89 has 2 decimal digits. But, 0.9 > 0.89.

Textbook page 34 · solved item 65

NCERT Class 7 Maths Chapter 3, solved question 65
Question from the current NCERT textbook

7. Mahi purchases 0.25 kg of beans, 0.3 kg of carrots, 0.5 kg of potatoes, 0.2 kg of capsicums, and 0.05 kg of ginger. Calculate the total weight of the items she bought.

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Beans = 0.25 kg Carrots = 0.3 kg Potatoes = 0.5 kg Capsicum = 0.2 kg Ginger = 0.05 kg Total weight = (0.25 + 0.3 + 0.5 + 0.2 + 0.05) kg = 1.3 kg

Textbook page 34 · solved item 66

NCERT Class 7 Maths Chapter 3, solved question 66
Question from the current NCERT textbook

8. Pinto supplies 3.79 L, 4.2 L, and 4.25 L of milk to a milk dairy in the first three days. In 6 days, he supplies 25 litres of milk. Find the total quantity of milk supplied to the dairy in the last three days.

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Milk supplied in first 3 days = 3.79 + 4.2 + 4.25 = 12.24 L Milk supplied in 6 days = 25 L Milk supplied in last three days = 25 L – 12.24 L = 12.76.

Textbook page 34 · solved item 67

NCERT Class 7 Maths Chapter 3, solved question 67
Question from the current NCERT textbook

9. Tinku weighed 35.75 kg in January and 34.50 kg in February. Has he gained or lost weight? How much is the change?

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Tinku’s weight: In January = 35.75 kg In February = 34.50 kg Change in weight = 35.75 kg − 34.50 kg = 1.25 kg Tinku has lost weight and the change in weight is 1.25 kg.

Textbook page 34 · solved item 68

NCERT Class 7 Maths Chapter 3, solved question 68
Question from the current NCERT textbook

10. Extend the pattern: 5.5, 6.4, 6.39, 7.29, 7.28, 6.18, 6.17, ____, _____.

Show solution

The current textbook appears to contain a printing error: 6.18 and 6.17 break the alternating pattern. Following the intended pattern of adding 0.90 and then subtracting 0.01 gives 5.5, 6.4, 6.39, 7.29, 7.28, 8.18, 8.17, 9.07, 9.06. Therefore, the blanks are 9.07 and 9.06.

Textbook page 34 · solved item 69

NCERT Class 7 Maths Chapter 3, solved question 69
Question from the current NCERT textbook

11. How many millimeters make 1 kilometer?

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1 km = 1000 m = (1000 × 100) cm = (100000 × 10) = 10,00,000 mm. Therefore, 10,00,000 mm make 1 km.

Textbook page 34 · solved item 70

NCERT Class 7 Maths Chapter 3, solved question 70
Question from the current NCERT textbook

12. Indian Railways offers optional travel insurance for passengers who book e-tickets. It costs 45 paise per passenger. If 1 lakh people opt for insurance in a day, what is the total insurance fee paid?

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Cost per passenger = ₹0.45 (i.e., 45 paise) Number of passengers = 1,00,000 Total insurance fee = 0.45 × 1,00,000 = 45 100× 1,00,000 = ₹45,000.

Textbook page 34 · solved item 71

NCERT Class 7 Maths Chapter 3, solved question 71
Question from the current NCERT textbook

13. Which is greater? (a) 10 1000 or 1 10 ? (b) One-hundredth or 90 thousandths? (c) One-thousandth or 90 hundredths?

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(a) 10 1000 or 1 10 10 1000 = 1 100 = 0.01 1 10 = 0.1 0.01 < 0.1 Therefore, 10 1000 < 1 10. (b) One-hundredth or 90 thousandths One-hundredth = 1 100 = 0.01 90 thousandths = 90 1000 = 9 100 = 0.09 0.01 < 0.09 Therefore, One-hundredth < 90 thousandths. (c) One-thousandth or 90 hundredths One thousandth = 1 1000 = 0.001 90 hundredths = 90 100 = 9 10 = 0.9 0.001 < 0.9 Therefore, One-thousandth < 90 hundredths.

Complete worked answers

Textbook page 35

Textbook page 35 · solved item 72

NCERT Class 7 Maths Chapter 3, solved question 72
Question from the current NCERT textbook

14. Write the decimal forms of the quantities mentioned (an example is given): (a) 87 ones, 5 tenths and 60 hundredths = 88.10 (b) 12 tens and 12 tenths (c) 10 tens, 10 ones, 10 tenths, and 10 hundredths (d) 25 tens, 25 ones, 25 tenths, and 25 hundredths

Show solution

(a) 87 ones, 5 tenths and 60 hundredths = (87 × 1) + (5 × 1 10) + (60 × 1 100) = 87 + 5 10 + 6 10 = 87 + 0.5 + 0.6 = 88.10 (b) 12 tens and 12 tenths = (12 × 10) + (12 × 1 10) = 120 + 12 10 = 120 + 1.2 = 121.2 (c) 10 tens, 10 ones, 10 tenths, and 10 hundredths = (10 × 10) + (10 × 1) + (10 × 1 10) + (10 × 1 100) = 100 + 10 + 1 + 1 10 = 111 + 10 + 1 + 0.1 = 111.1 (d) 25 tens, 25 ones, 25 tenths, and 25 hundredths = (25 × 10) + (25 × 1) + (25 × 1 10) + (25 × 1 100) = 250 + 25 + 25 10 + 25 100 = 250 + 25 + 2.5 + 0.25 = 277.75

Textbook page 35 · solved item 73

NCERT Class 7 Maths Chapter 3, solved question 73
Question from the current NCERT textbook

15. Using each digit 0 – 9 not more than once, fill the boxes below so that the sum is closest to 10.5:

Show solution

One exact completion is 4.083 + 6.417 = 10.500. No digit is repeated within the two addends.

Textbook page 35 · solved item 74

NCERT Class 7 Maths Chapter 3, solved question 74
Question from the current NCERT textbook

16. Write the following fractions in decimal form: (a) 1 2 (b) 3 2 (c) 1 4 (d) 3 4 (e) 1 5 (f) 4 5

Show solution

(a) 1 2 = 1 2 × 1 4 0 8 3 6 4 1 7 1 0 5 0 0 = 1 2 × 10 10 = 5 10 = 0.5 (b) 3 2 = 3 2 × 1 = 3 2 × 10 10 = 15 10 = 1.5 (c) 1 4 = 1 4 × 1 = 1 4 × 100 100 = 25 100 = 0.25 (d) 3 4 = 3 4 × 1 = 3 4 × 100 100 = 75 100 = 0.75 (e) 1 5 = 1 5 × 1 = 1 5 × 10 10 = 2 10 = 0.2 (f) 4 5 = 4 5 × 1 = 4 5 × 10 10 = 8 10 = 0.8

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